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As stated in the statement of the question, EF is a bisector of CD, so point G is the median point of CD, so CG = GD
5X - 1 = 7X - 13
X = 6
EF = EG + GF
6X - 4 = EG + 13 x = 6, so
6·6 - 4 = EG + 13
<h2>EG = 19</h2><em>(see attachment)</em>
The y values from:
1. ₋6
2. ₋3
3. 0
4. 3
Given the x values and y value as y = 3x
1. when x = ₋2 then y = 3x
y = 3(₋2)
y = ₋6
2. when x = ₋1 then y = 3x
y = 3(₋1)
y = ₋3
3. when x = 0 then y = 3x
y = 3(0)
y = 0
4. when x = 1 then y = 3x
y = 3(1)
y = 3
therefore we get the points as (₋2 , ₋6) (₋1 , ₋3) (0,0) (1 , 3).The graph is pltted and attached.
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Answer:
Step-by-step explanation:
The missing image is attached below.
From the given information
The number of players is 44.
From the box plot;
The minimum weight = 154 pounds
The first quartile Q₁ = 159 which is 25% of the data below 159 pounds.
The second quartile Q₂ = 213 which is 50% of the data below 213 pounds
The third quartile Q₃ = 253 which is 75% of the data below 253 pounds
The maximum weight = 268 pounds.
Here, the value of 213 is the middle value and which signifies the median.
The 50% of the data are located both on the left side and the right side of the median.
Thus, the percentage of players weighting greater than or equal to 213 pounds is 50%.
