Answer:
B
Step-by-step explanation:
In the case of this distance, trying to imagine 5 x 10^6 is obviously way too ridiculous
Answer:
x = 20√2 and y = 20√3.
or x = 28.28 and y = 34.64 to the nearest hundredths.
Step-by-step explanation:
Take the 2 'inside' triangles. They are similar.
So we have x / (60-40) = 40 / x
x/ 20 = 40 /x
x^2 = 800
x = √800
x = 20√2
y = √(800 + 20^2)
= √(1200)
= 20√3.
In the ordered pair (2, 12), x = 2 and y = 12.
Substitute these values into each inequality to see if the resulting inequality is true.
y > 2x + 4
12 > 2(2) + 4 Twelve is greater than 2 times 2 plus 4 ...hmmm
12 > 4 + 4
12 > 8 Twelve is greater than 8 ....this is TRUE...go to the next inequality
y < 3x + 7
12 < 3(2) + 7 Twelve is less than 3 times 2 plus 7 ...interesting
12 < 6 + 7
12 < 13 Twelve is less than 13 ... this is TRUE also
Therefore; the answer is b. Yes
It must create a true inequality for BOTH inequalities in order for the ordered pair to be a solution
Find the area of a triangle with base of 6 m and altitude of 4 m.
12
1. Multiply
2. Divide
1. Multiply by 4 on both sides
2. Divide by 7 on each side
Y = 8
