we know the x-intercept of the line is 1, recall that an x-intercept is when the graph intercepts or touches the x-axis, and when that happens, y = 0, so the point is really x = 1, y = 0, namely (1,0). We also know another point on the line, is (-2, 9).
Can you retype whatever you’re asking in this please?
Slope-Intercept Form: y=mx+b
Standard Form: ax+by=c
Point- Slope: (y-y1)= m(x-x1)
There are multiple answers to your question-
- If you are only missing b(the y-intercept) but are given a set of points, plug the points into x and y and solve for b.
- If you are only missing the slope(m) but are given a set of points, plug the points into x and y and solve for m.
- If you are given the standard form/point-slope form, change the equation to slope intercept form.
- If you are given an complete form(there is an x and y; no missing variables), but are not sure what it is, plug in some numbers in x to find y, then graph.
7 dollars each game and I know that because 10 would be 60 plus 16 which is way over and 5 would be 25 plus 16 which is incorrect 6 would be 30 which adding 16 would be 46. FINALLY ADDING 5 extra which is 7 times which is 35 plus 16 is 51.
Hope this helped
:D
