1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yarga [219]
3 years ago
15

$10 000 is borrowed at 10.5% per annum interest. How much interest is owed at the end of the first 10 months?

Mathematics
1 answer:
Leviafan [203]3 years ago
8 0

Answer:

$875 is the interest owed at the end of the first 10 months

Step-by-step explanation:

In this question, we are to calculate how much interest is owed in the first ten months.

There are several routes to this but the one i will like to use is as follows.

we shall calculate the amount owed for a year, afterwards we did use this amount by 12 since there are 12 months in a year. Now we multiply whatever answer we have by 10 to get the amount owed in 10 months.

To calculate the interest, we use the simple interest formula.

Mathematically;

I = PRT/100

where P is the amount borrowed which is $10,000

R is the interest rate which is 10.5% per annum

T is the time which we agreed we would be using 1 year first.

I = (10,000 * 10.5 * 1)/100 = $1050

This is the amount in 12 months. In a single month, this will be 1050/12 = $87.5

This amount in 10 months will be 87.5 * 10 = $875

You might be interested in
What is the probability of picking an "s" in the word "footloose"?
lbvjy [14]
1/9 or 0.1111111...%
8 0
4 years ago
Read 2 more answers
As a salesperson, you are paid $50 per week plus $2 per sale. This week you want your pay to be at least $100. What is the minim
mamaluj [8]
This is simple , minus 50 from 100 and that gives you 50 left . then divide that by 2 and that gives you 25 . so the minimum number of sales required is 25 . hope this helps :)<span />
8 0
3 years ago
Read 2 more answers
MARKING AS BRAINLIEST!! Starr if given functions are inverse)!
Kitty [74]

Answer: They are inverses of each other

==========================================================

Explanation:

We'll need to compute h(f(x)) and f(h(x)) to see if we get x each time.

h(x) = 9x-4\\\\h(f(x)) = 9(f(x))-4\\\\h(f(x)) = 9\left(\frac{x+4}{9}\right)-4\\\\h(f(x)) = x+4-4\\\\h(f(x)) = x\\\\

and,

f(x) = \frac{x+4}{9}\\\\f(h(x)) = \frac{h(x)+4}{9}\\\\f(h(x)) = \frac{9x-4+4}{9}\\\\f(h(x)) = \frac{9x}{9}\\\\f(h(x)) = x\\\\

Both composite functions lead to x each time.

The equations h(f(x)) = x and f(h(x)) = x being true means each function is the inverse of the other.

5 0
3 years ago
Read 2 more answers
Hey hi how you doing
sleet_krkn [62]

Answer:

Step-by-step explanation:

Nice and you?

3 0
2 years ago
Dante and Tania are both math tutors. The amount Dante charges for a session h hours long is represented by the function (h) =
Ksivusya [100]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
Other questions:
  • Solve this problem:<br><br><br><br> X+7=12
    15·1 answer
  • A business has $10,000 in its bank account. In order to build an addition onto its office, it takes out a loan for $30,000 and d
    10·1 answer
  • If Layla gets paid $948 a slow week . The employees Marco gets paid $9 an hour ,Stephanie gets paid $10.50 an hour ,and Destiny
    14·1 answer
  • How much will it cost for the family of four
    11·1 answer
  • Un inversionista desea comprar acciones de dos tipos. Las de tipo A generan un interés simple a razón de una tasa de 0,5 % mensu
    6·1 answer
  • Which expression represents the statement below: Four more than triple a number Group of answer choices 3X + 4 2(4x) 4(3X) 3X -
    7·1 answer
  • Adding fractions with unlike denominators​
    8·1 answer
  • What did the student do wrong?
    14·1 answer
  • An airplane flying at an altitude of 12000 feet begins ascending at a rate of 900 per minute. At this rate, how many minutes wil
    10·1 answer
  • What’s the solution to 2x - 2 &gt; 2x + 4 ?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!