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3 years ago

Which system of equations does not have a real solution

Mathematics

1 answer:

Aloiza [94]3 years ago

5 0

Answer:

the correct answer is y = x 2 + 3x - 5 and x + y = -10

Step-by-step explanation:

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Which of these numbers are rational? (Choose all that apply)

dezoksy [38]

Answer:

-7

Step-by-step explanation:

3 0

2 years ago

How r u so good at this

iren [92.7K]

Answer:

Step-by-step explanation:

Good at what?

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3 years ago

Read 2 more answers

I have a math question I need help answering.

aniked [119]

The answer should be $21,840.50

Explanation:

20000*1.045=a (first year)
a*1.045=b (second year)
b = 21840.5

6 0

2 years ago

Find the volume and area for the objects shown and answer Question

klio [65]

Step-by-step explanation:

You must write formulas regarding the volume and surface area of the given solids.

$\bold{\#1\ Rectangular\ prism:}\\\\V=lwh\\SA=2lw+2lh+2wh=2(lw+lh+wh)\\\\\bold{\#2\ Cylinder:}\\\\V=\pi r^2h\\SA=2\pi r^2+2\pi rh=2\pir(r+h)\\\\\bold{\#3\ Sphere:}\\\\V=\dfrac{4}{3}\pi r^3\\SA=4\pi r^2$

$\bold{\#4\ Cone:}\\\\V=\dfrac{1}{3}\pi r^2h\\\\\text{we need calculate the length of a slant length}\ l\\\text{use the Pythagorean theorem:}\\\\l^2=r^2+h^2\to l=\sqrt{r^2+h^2}\\\\SA=\pi r^2+\pi rl=\pi r^2+\pi r\sqrt{r^2+h^2}=\pi r(r+\sqrt{r^2+h^2})\\\\\bold{\#5\ Rectangular\ Pyramid:}\\\\V=\dfrac{1}{3}lwh\\\\$

$\\\text{we need to calculate the height of two different side walls}\ h_1\ \text{and}\ h_2\\\text{use the Pythagorean theorem:}\\\\h_1^2=\left(\dfrac{l}{2}\right)^2+h^2\to h_1=\sqrt{\left(\dfrac{l}{2}\right)^2+h^2}=\sqrt{\dfrac{l^2}{4}+h^2}=\sqrt{\dfrac{l^2}{4}+\dfrac{4h^2}{4}}\\\\h_1=\sqrt{\dfrac{l^2+4h^2}{4}}=\dfrac{\sqrt{l^2+4h^2}}{\sqrt4}=\dfrac{\sqrt{l^2+4h^2}}{2}$

$\\\\h_2^2=\left(\dfrac{w}{2}\right)^2+h^2\to h_2=\sqrt{\left(\dfrac{w}{2}\right)^2+h^2}=\sqrt{\dfrac{w^2}{4}+h^2}=\sqrt{\dfrac{w^2}{4}+\dfrac{4h^2}{4}}\\\\h_2=\sqrt{\dfrac{w^2+4h^2}{4}}=\dfrac{\sqrt{w^2+4h^2}}{\sqrt4}=\dfrac{\sqrt{w^2+4h^2}}{2}$

$SA=lw+2\cdot\dfrac{lh_1}{2}+2\cdot\dfrac{wh_2}{2}\\\\SA=lw+2\!\!\!\!\diagup\cdot\dfrac{l\cdot\frac{\sqrt{l^2+4h^2}}{2}}{2\!\!\!\!\diagup}+2\!\!\!\!\diagup\cdot\dfrac{w\cdot\frac{\sqrt{w^2+4h^2}}{2}}{2\!\!\!\!\diagup}\\\\SA=lw+\dfrac{l\sqrt{l^2+4h^2}}{2}+\dfrac{w\sqrt{w^2+4h^2}}{2}\\\\SA=\dfrac{2lw}{2}+\dfrac{l\sqrt{l^2+4h^2}}{2}+\dfrac{w\sqrt{w^2+4h^2}}{2}\\\\SA=\dfrac{2lw+l\sqrt{l^2+4h^2}+w\sqrt{w^2+4h^2}}{2}$

6 0

3 years ago

If f(x)=2x+1f(x)=2x+1f, left parenthesis, x, right parenthesis, equals, 2, x, plus, 1 and g(x)=x^2+7g(x)=x

nadya68 [22]

The value of the composite function f(g(x)) is 2x^2 + 15

<h3>How to evaluate the composite function f(g(x))?</h3>

The functions are given as:

f(x) = 2x + 1

g(x) = x^2 + 7

We have the function f(x) to be

f(x) = 2x + 1

Substitute g(x) for x in the equation f(x) = 2x + 1

So, we have

f(g(x)) = 2g(x) + 1

Substitute g(x) = x^2 + 7 in the equation f(g(x)) = 2x + 1

f(g(x)) = 2(x^2 + 7) + 1

Open the brackets

f(g(x)) = 2x^2 + 14 + 1

Evaluate the sum

f(g(x)) = 2x^2 + 15

Hence, the value of the composite function f(g(x)) is 2x^2 + 15

Read more about composite function at

brainly.com/question/10687170

#SPJ1

<u>Complete question</u>

if f(x) = 2x + 1 and g(x) = x^2 + 7

which of the following is equal to f(g(x))

8 0

1 year ago