Answer:
3(6)-1
----------------
2(6)+1
Step-by-step explanation:
r(x) = 3x-1
s(x) = 2x+1
r(6) / s(6)
r(6) = 3(6)-1
s(6) = 2(6)+1
Putting r(6)/ s(6)
3(6)-1
----------------
2(6)+1
Answer:
7.6 seconds
Step-by-step explanation:
To solve this problem we can use the following equation:
S = So + 113*t + at^2/2
Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.
In this problem, we have that S = 0, So = 65, Vo = 113 and a = -32 ft/s2 (The acceleration of gravity)
So we have that:
0 = 65 + 113t - 16t2
16t2 - 113t - 65 = 0
Using Bhaskara's formula, we have:
Delta = 113^2 + 4*65*16 = 16929
sqrt(Delta) = 130.11
t = (113 + 130.11) / (2*16) = 7.597 seconds
Rounding to nearest tenth, we have t = 7.6 seconds
Answer:
a
Step-by-step explanation:
Ac and BE are the diameters of a circle F
diameter passes through the centre
