Answer:
0.8024
Explanation:
From the given question; we can say that the angular momentum of the system is conserved if the net torque is is zero.
So; 
At the closest distance ; the friction is :

According to Newton's Law:
F = ma
F = mrω²
From conservation of momentum:



However ; since the static friction is producing the centripetal force :


The coefficient of static friction between the bottoms of your feet and the surface of the turntable can now be calculated by using the formula :

= 
= ![[\frac{1200+(73(6)^2)}{((1200)+(73)(3)^2)} ]^2*[\frac{(\frac{\pi}{4})^2(3)} {9.8}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1200%2B%2873%286%29%5E2%29%7D%7B%28%281200%29%2B%2873%29%283%29%5E2%29%7D%20%5D%5E2%2A%5B%5Cfrac%7B%28%5Cfrac%7B%5Cpi%7D%7B4%7D%29%5E2%283%29%7D%20%7B9.8%7D%5D)
= 0.8024
The work that need to do is 66.24 J.
<h3>Explanation :</h3>
Hello guys, before we can count how much the work that needed to pull the toy, we should know how formula to count it first. Because the movement is with the angle, so the formula is :

If :
- W = work (J)
- F = force (N)
- s = shift (m)
- θ = elevation angle (°)
We know that :
- x = the horizontal shift = 9,2 m
- θ = elevation angle = 15°
W = work = ... J

So, the work that need to do is 66.24 J.
<u>Subject</u><u> </u><u>:</u><u> </u><u> </u><u>Physics</u><u> </u>
<u>Class</u><u> </u><u>:</u><u> </u><u>Junior</u><u> </u><u>High</u><u> </u><u>School</u><u>/</u><u>Senior</u><u> </u><u>High</u><u> </u><u>School</u><u> </u>
<u>Keyword</u><u> </u><u>:</u><u> </u><u>Work</u><u>;</u><u> </u><u>Force</u><u>;</u><u> </u><u>Shift</u><u>;</u><u> </u><u>and</u><u> </u><u>Elevation</u><u> </u><u>Angle</u><u> </u>
False because the first law of motion is the crash I think I’m in middle school
In order for work to be done a force must be exerted on an object causing it to move
The practice of playing top hits several times a day on radio stations is called rotation.