Set up a proportion
1 mile/1.6 km = 20,000miles/x
Cross Multiply
x = (20,000) * (1.6)
x = 32,000 kilometers
Answer:
Explanation:
General equation of the electromagnetic wave:
![E(x, t)= E_0sin[\frac{2\pi}{\lambda}(x-ct)+\phi ]](https://tex.z-dn.net/?f=E%28x%2C%20t%29%3D%20E_0sin%5B%5Cfrac%7B2%5Cpi%7D%7B%5Clambda%7D%28x-ct%29%2B%5Cphi%20%5D)
where
Phase angle, 0
c = speed of the electromagnetic wave, 3 × 10⁸
wavelength of electromagnetic wave, 698 × 10⁻⁹m
E₀ = 3.5V/m
Electric field equation
![E(x, t)= 3.5sin[\frac{2\pi}{6.98\times10^{-7}}(x-3\times 10^8t)]\\\\E(x, t)= 3.5sin[{9 \times 10^6}(x-3\times 10^8t)]\\\\E(x, t)= 3.5sin[{9 \times 10^6x-2.7\times 10^{15}t)]](https://tex.z-dn.net/?f=E%28x%2C%20t%29%3D%203.5sin%5B%5Cfrac%7B2%5Cpi%7D%7B6.98%5Ctimes10%5E%7B-7%7D%7D%28x-3%5Ctimes%2010%5E8t%29%5D%5C%5C%5C%5CE%28x%2C%20t%29%3D%203.5sin%5B%7B9%20%5Ctimes%2010%5E6%7D%28x-3%5Ctimes%2010%5E8t%29%5D%5C%5C%5C%5CE%28x%2C%20t%29%3D%203.5sin%5B%7B9%20%5Ctimes%2010%5E6x-2.7%5Ctimes%2010%5E%7B15%7Dt%29%5D)
Magnetic field Equation
![B(x, t)= B_0sin[\frac{2\pi}{\lambda}(x-ct)+\phi ]](https://tex.z-dn.net/?f=B%28x%2C%20t%29%3D%20B_0sin%5B%5Cfrac%7B2%5Cpi%7D%7B%5Clambda%7D%28x-ct%29%2B%5Cphi%20%5D)
Where B₀= E₀/c

![B(x, t)= 1.2\times10^{-8}sin[\frac{2\pi}{6.98\times10^{-7}}(x-3\times 10^8t)]\\\\B(x, t)= 1.2\times10^{-8}sin[{9 \times 10^6}(x-3\times 10^8t)]\\\\B(x, t)= 1.2\times10^{-8}sin[{9 \times 10^6x-2.7\times 10^{15}t)]](https://tex.z-dn.net/?f=B%28x%2C%20t%29%3D%201.2%5Ctimes10%5E%7B-8%7Dsin%5B%5Cfrac%7B2%5Cpi%7D%7B6.98%5Ctimes10%5E%7B-7%7D%7D%28x-3%5Ctimes%2010%5E8t%29%5D%5C%5C%5C%5CB%28x%2C%20t%29%3D%201.2%5Ctimes10%5E%7B-8%7Dsin%5B%7B9%20%5Ctimes%2010%5E6%7D%28x-3%5Ctimes%2010%5E8t%29%5D%5C%5C%5C%5CB%28x%2C%20t%29%3D%201.2%5Ctimes10%5E%7B-8%7Dsin%5B%7B9%20%5Ctimes%2010%5E6x-2.7%5Ctimes%2010%5E%7B15%7Dt%29%5D)
Answer:
I think the answer might be the 2nd one or 3rd one.
Explanation :
Work is done when a force is applied to create a displacement on an object.
Thus, the work done depends on the two factors i.e.
(1) Applied force (F)
(2) Distance or displacement (d)
Mathematically, work done is 
It also depends on the angle between the force and the displacement.

For example,
A person carries a weight of 20 kg and lifts it on his head 1.5 m above the surface. So, the work done by him on the luggage will be:

or


So, 
Hence, the work done by him on the luggage is 294 Joules.