3 years ago

The table below shows data for a class's mid-term and final exams:

Mathematics

1 answer:

kari74 [83]3 years ago

4 0

I think it’s the 81-78

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Simplify 36x^4 42x^7

Alja [10]

The first step to simplify this equation is to multiply the numbers
1512 $x^{4}$ × $x^{7}$
next,, youll multiply the terms with the same base by adding their exponents
1512 $x^{4+7}$
finally,, youll add the numbers together
1512 $x^{11}$
since you cant simplify any further,, the correct answer to your question is 1512 $x^{11}$
let me know if you have any further questions
:)

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3 years ago

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The mean for class A is 82

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Nimfa-mama [501]

Answer:

Step-by-step explanation:

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Delvig [45]

Answer: A, C, and D all round to 5.6

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3 years ago

Consider the problem $minimize$ $f(x)=x^4-1$. solve this problem using newton's method. start from $x_0=4$ and perform three ite

stellarik [79]

F(x)=x⁴-1
f'(x)=4x³
Newton’s Method: x[n+1]=x[n]-f(x[n])/f'(x[n]); x[n+1]=x[n]-(x[n]⁴-1)/4x[n]³
x₁=3.00390625
x₂=2.26215...
x₃=1.7182...

X'=X-(X⁴-1)/4X³=X-X/4+1/4X³ is a symbolic way of writing the recursive formula, where X' represents the next iteration.
When X'≈X, -X/4+1/4X³≈0; so X/4≈1/4X³; X≈1/X³, so X⁴≈1 and X⁴-1≈0. But this is f(x)≈0. Hence Newton’s Method converges to a solution.
The rate of change is x[n+1]-x[n]=-(x[n]⁴-1)/4x[n]³=x[n]/4-1/4x[n]³ or symbolically -X/4+1/4X³.
Note that the method converges to one solution. A different x₀ will possibly converge to the solution x=-1.

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3 years ago