Use the difference of 2 squares (a - b)(a + b) = a^2 - b^2:-
(x - 1/x)(x + 1/x) = x^2 - (1/x)^2
= x^2 - 1/x^2
(x ^2 - 1/x^2)(x^2 + 1 /x^2)
= x^4 - 1/x^4
(x^4 - 1/x^4)(x^4 + 1/x^4)
= x^8 - 1 /x^8 Answer
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The coordinates of the pre-image of point F' is (-2, 4)
<h3>How to determine the coordinates of the pre-image of point F'?</h3>
On the given graph, the location of point F' is given as:
F' = (4, -2)
The rule of reflection is given as
Reflection across line y = x
Mathematically, this is represented as
(x, y) = (y, x)
So, we have
F = (-2, 4)
Hence, the coordinates of the pre-image of point F' is (-2, 4)
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