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HACTEHA [7]
3 years ago
11

What volume of H2O(g) is produced when 6.10 mol of C2H4(g) reacts at STP?

Chemistry
1 answer:
fgiga [73]3 years ago
8 0
Each mole of C₂H₄ produces 2 moles of H₂O
Moles of H₂O produced = 2 x 6.1
= 12.2 moles

Each mole of gas occupies 22.4 L at STP

Volume of H₂O = 22.4 x 12.2
= 273.28 Liters
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Answer:

0.962 atm.

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Explanation:

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In this case, given the available factors equaling 1 atm of pressure, each required pressure turns out:

- Atmospheres: 1 atm = 760 mmHg:

p=731mmHg*\frac{1atm}{760mmHg} =0.962atm

- Kilopascals:: 101.3 kPa = 760 mmHg:

p=731mmHg*\frac{101.3kPa}{760mmHg} =97.4kPa

- Torrs: 760 torr = 760 mmHg:

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- Pounds per square inch: 14.69 psi = 760 mmHg:

p=731mmHg*\frac{14.69}{760mmHg} =14.1psi

- Pascals: 101300 Pa = 760 mmHg:

p=731mmHg*\frac{101300Pa}{760mmHg} \\\\p=97,434.6Pa

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