The number of subshells in any given shell is equal to that shell's number. So the first shell (n=1) contains 1 subshell (1s). The second shell (n=2) contains 2 subshells (2s and 2p). The third shell (n=3) contains 3 subshells (3s, 3p, and 3d), and the fourth shell (n=4) contains 4 subshells (4s, 4p, 4d, and 4f).
<span>All d-type subshells have 5 orbitals, regardless of which shell they're in. s-type subshells contain 1 orbital each, p-type subshells contain 3 orbitals each, and f-type subshells contain 7 orbitals each. The answer would still be "five" even if you'd said 3d, 4d, or 6d...they all have five orbitals. </span>
Answer:
3 (s,p,d)
Explanation:
Principle energy levels number of sublevels number of electrons
1 1s 2n² = 2(1)²= 2
2 2s 2n² = 2(2)²= 8
2p
3 3s 2n² = 2(3)²= 18
3p
3d
when an atom has 3 energy level it has 1 sublevel (s) in 1st energy level 2 sublevels (s ans p) in second energy and three sublevels in third energy level (s,p,d). This atom with n=3 can accommodate 18 electrons in these sublevels.
Lava is your answer.
Lava is molten rock that is spewed from a volcano when in eruption. Once cooled and hardened (usually through long periods of time or with contact to large bodies of water), the lava would harden and mix with other materials, allowing it to form into igneous rocks.
hope this helps
Electrons contribute greatly to the atom's charge, as each electron has a negative charge equal to the positive charge of a proton. Scientists define these charges as “+1” and “-1. ” In an uncharged, neutral atom, the number of electrons orbiting the nucleus is equal to the number of protons inside the nucleus.:
Answer:
the final volume of the gas is = 1311.5 mL
Explanation:
Given that:
a sample gas has an initial volume of 61.5 mL
The workdone = 130.1 J
Pressure = 783 torr
The objective is to determine the final volume of the gas.
Since the process does 130.1 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.
Converting the external pressure to atm ; we have
External Pressure :
The workdone W = V
The change in volume ΔV=
ΔV =
ΔV =
ΔV = 1.25 L
ΔV = 1250 mL
Recall that the initial volume = 61.5 mL
The change in volume V is
multiply through by (-), we have:
= 1250 mL + 61.5 mL
= 1311.5 mL
∴ the final volume of the gas is = 1311.5 mL