Answer:
sin
(
x/
2
) = -
√
3
/2
Take the inverse sine of both sides of the equation to extract x
from inside the sine.
x/
2
=
arcsin
(
−
√
3/
2
)
The exact value of arcsin
(
−
√
3
/2
) is −
π
/3
.
/x
2
=
−
π
/3
Multiply both sides of the equation by 2
.
2
⋅
x
/2
=
2
⋅
(
−
π
/3
)
Simplify both sides of the equation.
x
=
−
2
π
/3
The sine function is negative in the third and fourth quadrants. To find the second solution, subtract the solution from 2
π
, to find a reference angle. Next, add this reference angle to π to find the solution in the third quadrant.
x
/2
=
2
π
+
π/
3
+
π
Simplify the expression to find the second solution.
x
=
2
π
/3
4
π
Add 4
π to every negative angle to get positive angles.
x
=
10
π
/3
The period of the sin
(
x
/2
) function is 4
π so values will repeat every 4
π radians in both directions.
x
=2
π
/3
+
4
π
n
,
10
π/
3
+
4
π
n
, for any integer n
Exclude the solutions that do not make sin
(
x
/2
)
=
−
√
3/
2 true.
x
=
10
π
/3
+
4
π
n
, for any integer n
Answer:
x = 2
Step-by-step explanation:
180= 90 + 57 + Z
Z = 180 - 90 - 57
Z = 33
33 = 7X + 19
7X = 33 - 19
7X = 14
X = 2
Answer:
Nice picture
Step-by-step explanation:
utoo............
Answer:
Price of 1 adult ticket is <u>$10.8</u> and Price of 1 children ticket is <u>$5.4</u>.
Step-by-step explanation:
Given:
Number of adults = 2
Number of Children = 6
Total Amount of tickets sold = $54.
We need to find the price of one children's ticket and one adult ticket.
Solution:
Let the Cost of 1 adult ticket be 'x'.
Now Given:
Children tickets are on sale,half price of adult tickets.
Cost of 1 Children ticket = 
Total Amount is equal to Number of adults multiplied by Cost of adult ticket plus Number of Children multiplied by Cost of Children ticket.
Framing in equation for we get;

Cost of 1 adult ticket = $10.8
Cost of 1 children ticket = 
Hence Price of 1 adult ticket is <u>$10.8</u> and Price of 1 children ticket is <u>$5.4</u>.
Answer:
Go to desmos and it will answer literally all of your graphing questions. Just type in desmos graphing calculator.
Step-by-step explanation: