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2 years ago

What is sum of 109 and h as an algebraic expression

Mathematics

1 answer:

sleet_krkn [62]2 years ago

4 0

Answer:

to be honest idon'tknow

Step-by-step explanation:

You might be interested in

Write the quadratic equation whose roots are 3 and -1, and whose leading coefficient is 5.

Assoli18 [71]

Answer:

5x² - 10x - 15 = 0

Step-by-step explanation:

Given that the roots are x = 3 and x = - 1, then the factors are

(x - 3) and (x + 1) and the quadratic is the product of the factors, that is

f(x) = a(x - 3)(x + 1) ← a is a multiplier

Here a = 5, thus

f(x) = 5(x - 3)(x + 1) ← expand factors using FOIL

= 5(x² - 2x - 3) ← distribute parenthesis by 5

= 5x² - 10x - 15

Thus equation is

5x² - 10x - 15 = 0

6 0

3 years ago

I can’t find this answer, help me plss

Vinvika [58]

2) 7/4×(22–x) =0

soln

= 7/4×(22 –x) =0

= 1.75 ×22 –x =0

= x=38.5

9) 15x² /7 =8x²/5

soln

= 15x²×8x²=7×5

=120x^4 = 35

= x^4 =120–35

x^4 =85

6) 9x²/4–4=0

soln

=9x²/4–4=0

=2.25–4=0

=4–2.25=0

=1.75

<h2>sorry I know that much </h2>

8 0

2 years ago

What is a real situation that would be represented by a+3

spin [16.1K]

A is just a variable to cover up any number you want. a can be anything you want, such as the money in your bank account.
a+3
a=200
200+3

7 0

2 years ago

A man is standing at a radar base and observes an unidentified plane at an altitude 6000m flying towards the radar base at an an

liubo4ka [24]

Answer:

The speed in of the plane is 115.47 m/sec

Step-by-step explanation:

Given:

Height at which the plane is flying = 6000 m

Angle of elevation at the radar base = 30 Degrees

Angle of elevation at the radar base after one minute = 60 Degrees

To Find:

The Speed of the plane in meter per second = ?

Solution:

Let us use the tangent of the angle to find the distance (d) to a point directly below plane:

when the angle is 30 degrees

$tan(30) = \frac{6000}{d1}$

$d1 = \frac{6000}{tan(30)}$

$d1 = \frac{6000}{0.577}$

d1 = 10392.3 meters

when the angle is 60 degrees

$tan(60) = \frac{6000}{d2}$

$d2 = \frac{6000}{tan(60)}$

$d2 = \frac{6000}{1.732}\\$

d2 = 3464.1 meters

distance travelled by aircraft in 1 min is

=>d1 - d2

=>0392.3 - 3464.1

= 6928.2 m/min

Now converting to m/sec

=> $\frac{6928.2}{60}$

=>115.47 m/sec

4 0

3 years ago

How do you factor this expression by dividing by the GCF first. 15c-25

chubhunter [2.5K]

15c-25
15c=25
your answer is c=13.5

4 0

3 years ago