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Dahasolnce [82]
3 years ago
6

The radius of the bull’s-eye of the dartboard is 8 inches. The radius of each concentric circle is 8 inches more than the radius

of the circle inside it. If a dart lands at random on the dartboard, what is the probability that the dart will hit in area C?
A. 9/16
B. 5/16
C. 1/4
D. 3/4

Mathematics
1 answer:
UNO [17]3 years ago
5 0

Answer with Step-by-step explanation:

The radius of the bull’s-eye of the dartboard is 8 inches.

The radius of each concentric circle is 8 inches more than the radius of the circle inside it.

Radius of first circle=8 in.

Radius of second circle=16 in.

Radius of third circle=24 in.

Radius of fourth circle=32 in.

Area of C=Area of the third circle-Area of second circle

                     = π×24×24-π×16×16

                   = 320π sq. in.

Total area of dartboard=Area of fourth circle=π×32×32

                                                            =1024π sq. in.

P( the dart will hit in area C)= area of c/total area of dart board

                                             =320π/1024π

                                           =  5/16

Hence, correct option is:

B.5/16

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Plssss help what is x
makvit [3.9K]

Answer:

x = 4

Step-by-step explanation:

If you do not want to read the explanation go the the next part in bold

Ok so the shorter leg of the triangle is a radius of the circle. ( This is indicated by the point in the middle of the circle.) for the hypotenuse we are given one part of the length (2) The other part also happens to be a radius ( remember that a radius is a line that starts from the center of the triangle to any point of the circumference. ) Also remember that the radius is equal to 3. That being said the hypotenuse = 2+3 which equals 5.  

This triangle then happens to be a right triangle. ( A triangle formed by a tangent line and a radius is a right triangle.) This means that we can use the Pythagorean theorem to solve for x.

Below here is where the work is shown

a² + b² = c². where a and b = legs and c = hypotenuse. We are given the hypotenuse (5) and a leg (3) So we plug in what we are given and solve for the missing information. 5² = 3² + b²  

5² = 25

3² = 9

we would then have 25 = 9 + b²

Next we subtract 9 from each side

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8 0
2 years ago
Please please help............
maksim [4K]
Part A Simplify:

Answer is - 12b + 6c + 18



Part B

Answer is (D)

Factor/simplify
- 12b + 6c + 18

6(- 2b + c + 3)
= (6)(- 2b + c + 3)
= (6)(- 2b ) + (6)(c) + (6)(3)
= - 12b + 6c + 18

therefore,- 12b + 6c + 18; Factored in GCF is 6(-2b + c + 3)





- 12b + 6c + 18
reorder the terms
18 + 12b + 6c

Factor out the GCF " 6"
6(3 + 2b + c)


Final Result:
6(3 + 2b + c)



Hope this helps
6 0
3 years ago
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