Here are the answers for the Unit 7 lesson 1 Geometry Practice!
1. C - If a line is tangent to a circle then...
2. D - 120 Degrees
3. B - 47 Degrees
4. C - 4.8 Units
5. A, B, D - A tangent line is perpendicular to the radius..., A tangent line is perpendicular to the diameter..., A tangent line intersects...
6. B - y = 2/3x + 1/3
7. A - 6.5
8. B, D - 8 & 4 square-root(21), 10 & 10 square-root(3)
9. A, C, D - 8 & 4 square-root(3), 3 & 5, 2 & 2 square-root(5)
10. D - 78 cm
Just took it these are 100%
F(x) = 4x^2 + 12
g(x) = x - 1
(f o g)(x) = f(g(x)) = 4(x - 1)^2 + 12 = 4(x^2 - 2x + 1) + 12 = 4x^2 - 8x + 4 + 12 = 4x^2 - 8x + 16
(f o g)(3) = 4(3)^2 - 8(3) + 16 = 4(9) - 24 + 16 = 36 - 8 = 28
We find the difference of the two numbers by subtracting the two numbers given above. It is calculated as follows:
Difference = 20000 - 4632 = 15368
Therefore, the difference between <span>4,632 and 20,000 is 15368.
Hope this answers the question. Have a nice day.</span>
Answer : (8,5)
Given
K(x) = ![8-\sqrt[3]{x}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7Bx%7D)
Now we plug in each point and check whether it satisfies our equation
(-64,12)
K(-64) = ![8-\sqrt[3]{-64}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B-64%7D)
= 12 so this point lie on graph
(125,3)
K(125) = ![8-\sqrt[3]{125}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B125%7D)
= 3 so this point lie on graph
(343,1)
K(343) = ![8-\sqrt[3]{343}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B343%7D)
= 1 so this point lie on graph
(8,5)
K(8) = ![8-\sqrt[3]{8}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B8%7D)
= 6 so this point does not lie on graph because we got 6 instead of 5
Can't see it the equation is to blurry.
