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eduard
3 years ago
14

Jannete has 326 pennies, 64 nickles, and 15 dimes. if she has to exchange her coins for dollars how many dollars will she have ?

how many cents will remain?
​
Mathematics
1 answer:
Vlad1618 [11]3 years ago
3 0

Answer:

She will have 7 dollars, with 96 cents remaining.

Step-by-step explanation:

326 pennies is $3.26

64 nickels is $3.20

15 dimes is $1.50

Add them all;

$3.26 + $3.20 + $1.50 = $7.96

She will have 7 dollars, with 96 cents remaining

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How do I solve this
hichkok12 [17]
You wanna find a common denominator so put the problem like this

3 1/3.< You wanna take 3 (denominator)
And times it
By 5 then you wanna take the 5. - 2 2/5.< (deniminator) and times it by 3.
____ Your common denominator is 15

now it will look like this

3 1/15

-2 2/15
———-

Now subtract. You will need to borrow 1 from 3 since you cant subtract 2 by 1 so the 3 will become a 2 and the 1 will be come 11 and here you can subtract so this will be your answer.

2 11/15

-2 2/15
-———-
0 9/15

Thats your official answer 9/15 hope I helped :)
4 0
3 years ago
Write the equation of the line that passes through the points (0, 6) and (3, 0) in slope-intercept form
damaskus [11]

Answer:y=-2x+6

Step-by-step explanation: Write in Slope-Intercept form, y=mx+b.

Hope this helps you out! ☺

8 0
3 years ago
1) There are 80 grams of salt in a 32% solution. Find the weight of the solution
alukav5142 [94]

Answer:

Weight of the solution = 250 grams

Step-by-step explanation:

1) Consider the weight of solution as x grams.

32 % solution = 80 grams salt

32% of x = 80

(32/100)*x = 80

Solving for x:

x  = (80*100) / 32

x = 250 grams

7 0
4 years ago
Whats the answer to this has me stumped
Thepotemich [5.8K]
Ànswer is A
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7 0
3 years ago
Joseph claims that a scatterplot in which the y-values increase as the x-values increase must have a linear association. Amy cla
My name is Ann [436]

Answer: Choice C

Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.

======================================================

Explanation:

Just because the data points trend upward (as you go from left to right), it does not mean the data is linearly associated.

Consider a parabola that goes uphill, or an exponential curve that does the same. Both are nonlinear. If we have points close to or on these nonlinear curves, then we consider the scatterplot to have nonlinear association.

Also, you could have points randomly scattered about that don't fit either of those two functions, or any elementary math function your teacher has discussed so far, and yet the points could trend upward. If the points are not close to the same straight line, then we don't have linear association.

-----------------

In short, if the points all fall on the same line or close to it, then we have linear association. Otherwise, we have nonlinear association of some kind.

Joseph's claim that an increasing trend is not enough evidence to conclude the scatterplot is linear or not.

8 0
3 years ago
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