Question

Dave is comparing the circumferences of several trees in his yard. The oak tree is 0.539 meters in circumference, the ash tree has a circumference of 0.509 yards, the elm tree is 6281.70 millimeters around, and the poplar has a circumference of 0.000385 miles. There are 30.48 centimeters in a foot. Which tree has the greatest circumference?
a. oak
b. ash
c. elm
d. poplar
Please select the best answer from the choices provided A B C D

Answer 1

Answer:   c. elm

Step-by-step explanation:

Given : The circumference of the oak tree= 0.539 meters

=$0.539\times100=53.9\text{ cm}$   [∵ 1 m = 100 cm]             (1)

The circumference of the ash tree= 0.509 yards

$=0.509\times3\text{ feet}$   [∵ 1 yard = 3 feet]

$=0.509\times3\times 30.48\text{ cm}$  [∵ 1 foot = 30.48 cm]

$=46.54296\approx46.54\text{ cm}$        (2)

The circumference of the elm tree = 6281.70 millimeters

$=\dfrac{6281.70}{10}=628.17\text{ cm}$          (3)

The circumference of the poplar tree = 0.000385 miles

$=0.000385 \times5280\text{ feet}$   [∵ 1 mile = 5280 feet]

$=0.000385 \times5280\times30.48\text{ feet}$  [∵ 1 foot = 30.48 cm]

$=61.959744\approx61.96\ \text{ cm}$              (4)

From (1) , (2) , (3 ) and (4) it is clear that

46.54< 53.9 < 61.96 < 628.17

Hence, the elm tree has the greatest circumference.