Question

Find three consecutive even integers such that the sum of the first, twice the second, three times the third is -76. What is the number?
(the three numbers is the same number)

Answer 1

Answer:

The numbers are -14,-13 and -12

Step-by-step explanation:

The correct question is

Find three consecutive integers such that the sum of the first, twice the second and three times the third is -76. What is the number?

Let

x ----> the first consecutive integer

x+1 ---> the second consecutive integer

x+2 ---> the third consecutive integer

we have that

$x+2(x+1)+3(x+2)=-76$

solve for x

apply distributive property

$x+2x+2+3x+6=-76$

Combine like terms

$6x+8=-76$

subtract 8 both sides

$6x=-76-8$

$6x=-84$

Divide by 6 both sides

$x=-14$

so

$x+1=-14+1=-13$

$x+2=-14+2=-12$

therefore

The numbers are -14,-13 and -12