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jonny [76]
2 years ago
14

The time period of a pendulum is 0.5 s. No of oscillations of the pendulum is 20. Find the time taken to complete 20 oscillation

s (with explanation pls)
Mathematics
2 answers:
pav-90 [236]2 years ago
8 0
  • Time period=0.5s
  • No if oscillations=20

\\ \sf\longmapsto Time\:period=\dfrac{Time\:taken}{No\:of\; oscillations}

\\ \sf\longmapsto Time\:taken=No\:of\: oscillations (Time\: period)

\\ \sf\longmapsto Time\:taken=20(0.5)

\\ \sf\longmapsto Time\:taken=10s

Cloud [144]2 years ago
7 0
<h2><u>Given</u> :</h2>

  • Time period = 0.5s
  • Number of oscillations = 20

<h2><u>What </u><u>To </u><u>Find</u> :</h2>

  • Time taken to complete 20 oscillations.

<h2><u>Formula </u><u>Using</u> :</h2>

\begin{gathered} {\underline{\boxed{ \rm {\red{Time \:  period \:  =  \: \frac{Time  \:  \: taken}{Number \:  of \:  oscillations}  }}}}}\end{gathered}

\begin{gathered} {\underline{\boxed{ \rm {\purple{Time  \: taken \:  =  \: Number  \: of \:  oscillations \: (Time \:  period)}}}}}\end{gathered}

<h2><u>Solution</u> :</h2>

\large \rightarrow \:  {\rm {{{\color{orange}{Time  \: taken \:  =  \: 20 (0.5)}}}}}

\large \rightarrow \:  {\rm {{{\color{orange}{Time  \: taken \:  =  \: 10s}}}}}

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The amount people pay for cable service varies quite a bit but the mean monthly fee is $142 and the standard deviation is $29. t
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Answer:

a) By the Central Limit Theorem, the mean is $142 and the standard deviation is $0.7488.

b) By the Central Limit Theorem, approximately normal.

c) 0.0901 = 9.01% probability that the average cable service paid by the sample of cable service customers will exceed $143

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean monthly fee is $142 and the standard deviation is $29.

This means that \mu = 142, \sigma = 29

Part a: what are the mean an standard deviation of the sample distribution of x hat show your work and justify your reasoning.

Sample of 1500(larger than 30).

By the Central Limit Theorem

The mean is $142

The standard deviation is s = \frac{29}{\sqrt{1500}} = 0.7488

Part b: what is the shape of the sampling distribution of x hat justify your answer.

By the Central Limit Theorem, approximately normal.

Part C: what is the probability that the average cable service paid by the sample of cable service customers will exceed $143?

This is 1 subtracted by the pvalue of Z when X = 143. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{143 - 142}{0.7488}

Z = 1.34

Z = 1.34 has a pvalue of 0.9099

1 - 0.9099 = 0.0901

0.0901 = 9.01% probability that the average cable service paid by the sample of cable service customers will exceed $143

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Then to figure out how many hours the worker needs to work, divide the goal by the hourly earnings. So

$333 / $18 = 18.5 hours.



Therefore on average, it will take 18.5 hours to earn $333, assuming a base salary of $6/hour and an average of $12 in tips per hour.
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