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Inessa05 [86]
3 years ago
5

What is this please help

Mathematics
2 answers:
alexdok [17]3 years ago
5 0

I am not exactly sure what the answer is but I remember when I was learning about it before. There is too much problem solving to remember all of them

Minchanka [31]3 years ago
5 0

Answer:

Da answer is 36

Step-by-step explanation:

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Write 83 as a sum of tens and ones
Hoochie [10]
Well,

We can see that there are 8 10's and 3 1's.  So we can write 8 10's followed by 3 1's and join them with addition symbols.

83 = 10 + 10 + 10 + 10 + 10 + 10 + 10 + 10 + 1 + 1 + 1
6 0
3 years ago
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-3 raised to the power 0=
son4ous [18]

Given:

The statement is "-3 raised to the power 0".

To find:

The value of the given expression.

Solution:

We know that a raised to the power b can be written as a^b.

Any non zero number raised to the power 0 is always 1. It means,

a^0=1, where a\neq 0.

-3 raised to the power 0 =(-3)^0

                                         =1

Therefore, the value of the given statement is 1.

3 0
3 years ago
A college chemistry instructor thinks the use of embedded tutors will improve the success rate in introductory chemistry courses
Yuliya22 [10]

Answer:

Step-by-step explanation:

Hello!

The chemistry instructor tested the hypothesis that the proportion of students that passed the introductory chemistry class is better with an embedded. If the known proportion for this population is 65%, the tested hypothesis is:

H₀: p=0.65

H₁: p>0.65

The calculated statistic is Z=2.52 and the associated p-value: 0.0059

Remember:

The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

In this case:

P(Z≥2.52)=0.0059

There is no significance level, the most common one is α: 0.05 so I'll use it as an example.

To make a decision using the p-value you have to compare it to the α.

If p- value>α then you support the null hypothesis (In this case, you can say that there is no change in the proportion of students that passed the introductory chemistry class with an embedded tutor.)

If p-value≤α your decision will be to reject the null hypothesis (In this case, there is significant evidence to say that there is an improvement in the success rate of the introductory chemistry class with an embedded tutor?

Since the p-value:0.0059 is less than the significance level 0.05, you will decide to reject the null hypothesis.

I hope you have a SUPER day!

8 0
3 years ago
What is 23 divided by 99 in decimal form
Yuki888 [10]
I think it would be 0.23 repeating so basically 0.23232323
5 0
3 years ago
Read 2 more answers
When parking a car in a downtown parking lot, drivers pay according to the number of hours or fraction thereof. The probability
Zigmanuir [339]

Answer:

u = 4.604 , s = 2.903

u' = 23.025 , s' = 6.49

Step-by-step explanation:

Solution:

- We will use the distribution to calculate mean and standard deviation of random variable X.

- Mean = u = E ( X ) = Sum ( X*p(x) )

 u = 1*0.229 + 2*0.113 + 3*0.114 + 4*0.076 + 5*0.052 + 6*0.027 + 7*0.031 + 8*0.358.

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- Standard deviation s = sqrt ( Var ( X ) = sqrt ( E ( X^2) + [E(X)]^2

 s = sqrt [ 1*0.229 + 4*0.113 + 9*0.114 + 16*0.076 + 25*0.052 + 36*0.027 + 49*0.031 + 64*0.358 - 4.604^2 ]

s = sqrt ( 8.429184 )

s = 2.903          

- We will use properties of E ( X ) and Var ( X ) as follows:

- Mean = u' = E (Rate*X) = Rate*E(X) = $5*u =

               u' = $5*4.605

               u' = 23.025

- standard deviation = s' = sqrt (Var (Rate*X) ) = sqrt(Rate)*sqrt(Var(X)) = sqrt($5)*s =

               s' = sqrt($5)*2.903

               u' = 6.49

3 0
3 years ago
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