Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.
Answer:
There is not enough evidence to conclude that average starting salary for clerical employees in the state is less than $35,000 per year.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 35,000 dollars per year
Sample mean, 
= 34,700 dollars per year
Sample size, n = 100
Alpha, α = 0.10
Population standard deviation, σ = 3,500 dollars per year
First, we design the null and the alternate hypothesis
We use one-tailed z test to perform this hypothesis.
Formula:
Putting all the values, we have
Now, 
Since,
We fail to reject the null hypothesis and accept the null hypothesis.
Thus, there is not enough evidence to conclude that average starting salary for clerical employees in the state is less than $35,000 per year.
