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netineya [11]
3 years ago
14

Line V has a slope of 8/9. Line w is perpendicular to V. What is the slope of line W?

Mathematics
1 answer:
Alex787 [66]3 years ago
6 0

Answer:

W = -9/8

Step-by-step explanation:

for two perpendicular lines

W*V = -1

W = 9/8*(-1)

W= -9/8

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9x3^15 can be written as 3^n. What is the value of n​
stich3 [128]
N=17
used a calculator
5 0
3 years ago
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-<br> -<br> What is the vertex of the quadratic function f(x) = (x - 6)(x + 2)?
kakasveta [241]

Answer:

X=6,x=-2

Step-by-step explanation:

To solve this question we will have to follow the step by step procedure

(x-6)(x+2)

x^2+2x-6x-12

Let's continue

x^2-4x-12

Let's factorise

x^2-6x+2x-12

x(x-6)+2(x-6)

(x-6)(x+2)

so to solve further that is to get the value for x

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x=6

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Substrate 2 from both sides

x=-2

Therefore x=6,x=-2

4 0
4 years ago
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Can someone please clearly and correctly solve and show me how to work out QUESTION 3 AND 4??
vredina [299]
There are 2 options to solve that.
1. The first one is by derivatives. 
f(x)=x^2+12x+36
f'(x)=2x+12
then you solve that for f'(x)=0
0=2x+12
x=(-6)
you have x so for (-6) solve the first equation, then you find y
y=(-6)^2+12*(-6)+36=(-72)
so the vertex is (-6, -72)
2. The second option is to solve that by equations:
for x we have:
x=(-b)/2a
for that task we have
b=12
a=1
x=(-12)/2=(-6)
you have x so put x into the main equation
y=(-6)^2+12*(-6)+36=(-72)
and we have the same solution: vertex is (-6, -72)

For next task, I will use the second option:
y=x^2-6x
x=(-b)/2a
for that task we have
b=(-6)
a=1
x=(6)/2=3
you have x so put x into the main equation
y=3^2+(-6)*3=(--9)
and we have the same solution: vertex is (3, -9)

3 0
3 years ago
A 64-ounce bottle costs $3.45. What is the cost per ounce? Round answer to the nearest cent.
Rufina [12.5K]

Answer:

$0.05

Step-by-step explanation:

3.45 divided by 64

5 0
3 years ago
Converting measures 48ft= yd​
Vera_Pavlovna [14]

Answer:

48 Feet (ft) 16.000 Yards (yd)

1 ft = 0.333333 yd 1 yd = 3.000000 ft

Step-by-step explanation:

5 0
3 years ago
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