Help me please with this thank you

1. The function, g, is graphed below. EXPLAIN how to find x, if g(x) = -1 in sufficient<br> detail

konstantin123 [22]

<h3>Answer: x = 1</h3>

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Explanation:

Step 1) Start at -1 on the y axis.
Step 2) Draw a horizontal line from -1 until you reach the g(x) curve.
Step 3) Mark the point of intersection. Let's call it point A.
Step 4) From point A, draw a vertical line until you reach the x axis. You should get to x = 1.

All of this is shown in the diagram below.

Now follow the arrows in reverse. This shows that x = 1 leads to y = g(x) = -1.

Therefore, g(1) = -1 and x = 1 is the solution to g(x) = -1.

Side note: The equation is g(x) = 2x-3. We can replace g(x) with -1 and solve for x to get x = 1.

4 0

3 years ago

Listed below are the number of years it took for a random sample of college students to earn bachelor's degrees (based on data f

schepotkina [342]

Answer:

a) Mean = 6.5, sample standard deviation = 3.50

b) Standard error = 0.7826

c) Point estimate = 6.5

d) Confidence interval: (5.1469 ,7.8531)

Step-by-step explanation:

We are given the following data set for students to earn bachelor's degrees.

4, 4, 4, 4, 4, 4, 4.5, 4.5, 4.5, 4.5, 4.5, 4.5, 6, 6, 8, 9, 9, 13, 13, 15

a) Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{130}{20} = 6.5$

Sum of squares of differences = 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 6.25 + 4 + 4 + 4 + 4 + 4 + 4 + 0.25 + 0.25 + 2.25 + 6.25 + 6.25 + 42.25 + 42.25 + 72.25 = 233.5

$S.D = \sqrt{\frac{233.5}{19}} = 3.50$

b) Standard Error

$= \displaystyle\frac{s}{\sqrt{n}} = \frac{3.50}{\sqrt{20}} = 0.7826$

c) Point estimate for the mean time required for all college is given by the sample mean.

$\bar{x} = 6.5$

d) 90% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.10} = \pm 1.729$

$6.5 \pm 1.729(\frac{3.50}{\sqrt{20}} ) = 6.5 \pm 1.3531 = (5.1469 ,7.8531)$

e) No, the confidence interval does not contain the value of 4 years. Thus, confidence interval is not a good estimator as most of the value in the sample is of 4 years. Most of the sample does not lie in the given confidence interval.

5 0

4 years ago

-30=3(y-6)-7y<br> What is y ??

bagirrra123 [75]

Answer:

I would say

y= 3

4 0

3 years ago

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