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SashulF [63]
3 years ago
13

Factor −5 out of −10a−25

Mathematics
1 answer:
kap26 [50]3 years ago
3 0

Answer:

-5(2a+5)

Step-by-step explanation:

Just divide all the numbers by -5, slap a parentheses on and your done.

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After Halloween, a variety store had some costumes regularly priced at $20.50 on sale for 20% off the regular price. A few weeks
Diano4ka-milaya [45]
20.50 * 0.8 = $16.40

16.40 * 0.4 = $6.56

Final selling price = $6.56
6 0
3 years ago
This is my question!<br> Please help answer!!!
svp [43]

The x and y coordinates of point S are increased by three to get to the midpoint.

(2,1) ----> (5,4)

To get to point t increase the coordinates by three again.

(5,4) -----> (8,7)

answer: (8,7)

6 0
4 years ago
Find the area of the composite figure.
Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

Length = 6 in

<u>To Find :</u>

The Area of the composite figure

<u>Solution:</u>

Firstly we need to find the area of Rectangular part.

So We know that,

\boxed{ \rm \: Area  \:  of \:  Rectangle = Length×Breadth}

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

\boxed{\rm \: Breadth = total  \: distance - Radius}

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

\longrightarrow\rm \: Length \:  of \:  the  \: circle = Radius

  • Since Length = 6 in ;

\longrightarrow \rm \: 6 \: in   = radius

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

  • Total Horizontal Distance= 14
  • Radius = 6

\longrightarrow\rm \: Breadth = 14-6

\longrightarrow\rm \: Breadth = 8 \: in

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

  • Length = 6
  • Breadth = 8

\longrightarrow\rm \: Area \:  of  \: Rectangle = 6 \times 8

\longrightarrow \rm \: Area \:  of  \: Rectangle = 48 \: in {}^{2}

Then, We need to find the area of Quarter circle :

We know that,

\boxed{\rm Area_{(Quarter \; Circle) }  = \cfrac{\pi{r} {}^{2} }{4}}

Now Substitute their values:

  • r = radius = 6
  • π = 3.14

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 6 {}^{2} }{4}

Solve it.

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 36}{4}

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}

\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9

\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \:  {in}^{2}

Now we can Find out the total Area of composite figure:

We know that,

\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}

So Substitute their values:

  • \rm Area_{(rectangle)} = 48
  • \rm Area_{(Quarter Circle)} = 28.26

\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26

Solve it.

\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

\rule{225pt}{2pt}

I hope this helps!

3 0
2 years ago
PLEASEEEEEEEEEEEEEEEEEEEEEE Edgar rolls two six-sided number cubes. What is the probability that he rolls a 2 on
frutty [35]

Answer:

The probability that he rolls a sum of 9 given the sample space is . 9/36, or 1/4.

What is the probability?

Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

The probability that he rolls a sum of 9 = cubes that have a sum of 9 / total number of cubes

9/36 = 1/4

5 0
2 years ago
F(r-2)=6(r-2)+7=6r-12+7
Gre4nikov [31]

Answer: D=22

Step-by-step explanation:

this is because if multiply f by r you get D and then you do all the other rmathematics and you wind up with 22

3 0
3 years ago
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