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RUDIKE [14]
2 years ago
12

Short-term classes: Does taking a class in a short-term format (8 weeks instead of 16 weeks) increase a student’s likelihood of

passing the course? For a particular course, the pass rate for the 16-week format is 59%. A team of faculty examine student data from 40 randomly selected accelerated classes and determine that the pass rate is 78%. Which of the following are the appropriate null and alternative hypotheses for this research question?
a.H0: p = 0.59; Ha: p ≠ 0.59
b.H0: p = 0.59; Ha: p > 0.59
c.H0: p = 0.78; Ha: p ≠ 0.78
d.H0: p = 0.78; Ha: p > 0.59
Mathematics
1 answer:
NemiM [27]2 years ago
3 0

Answer:

Option b

Step-by-step explanation:

Given that For a particular course, the pass rate for the 16-week format is 59%. A team of faculty examine student data from 40 randomly selected accelerated classes and determine that the pass rate is 78%.

we have to find whether  taking a class in a short-term format (8 weeks instead of 16 weeks) increase a student’s likelihood of passing the course

Since pass rate for 16 weeks is 59% we check whether for 8 weeks is more than this.

So correct null and alternative hypotheses for this research question

would be:

b.H0: p = 0.59; Ha: p > 0.59

Option b is right.

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Answer:

3 + 2 = 5

5 x 5 = 25(5^2 = 25)

25 - 7 = 18

Step-by-step explanation:

Solve in parenthesis first then do exponents then perform the subtraction.

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3 years ago
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Answer:

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Please tell me which are correct
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3 years ago
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Mr. Falk is going to replace the carpet in his basement. The basement is
Rzqust [24]
<h3>Answer:  1728 dollars</h3>

==========================================================

Explanation:

1 yard = 3 feet

We'll divide by 3 to convert from feet to yards

  • 27 feet = 27/3 = 9 yards
  • 18 feet = 18/3 = 6 yards

The basement is 9*6 = 54 square yards in floor area.

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7 0
2 years ago
The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain? {5, 8} {-5, -8} {3, 8} {4, 7} {4, 8}
Savatey [412]
The range is the ouutput from inputing the input
basically
25=k²+2k+1 and 64=k²+2k+1
the values that satisfy both equations (not at the same tim) are the valuess that are the domain
solve each
25=k²+2k+1
minus 25 both sides (or recognize the perfect square trinomial, but anyway)
0=k²+2k-24
factor
0=(k+6)(k-4)
set to zero
k+6=0
k=-6
k-4=0
k=4
k=-6 or 4

64=k²+2k+1
minus 64 both sides
0=k²+2k-63
facor
0=(k-7)(k+9)
set to zer
k-7=0
k=7
k+9=0
k=-9
k=-9 or 7



so the domain has the numbers
-9,-6,4,7
it seems we only want the positive square roots so
answer is {4,7} is the domain
3 0
3 years ago
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