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Greeley [361]
3 years ago
6

SHOPPING Sera went to the mall and made four purchases. She spent $2.85, $5.11, $7.89, and $4.15. Use mental math to determine h

ow much money Sera spent at the mall.
Mathematics
2 answers:
djverab [1.8K]3 years ago
6 0

Answer:

$20.00  

Step-by-step explanation:

  $2.85 =   3.00  - 0.15

  $5.11   =   5.00 + 0.11

  $7.89 =   8.00 + 0.11      Mentally cancel the 0.11s

  $4.15 =   4.00 + 0.15     Mentally cancel the 0.15s

TOTAL = 20.00 + 0.00

TOTAL = $20.00

Katena32 [7]3 years ago
4 0

Answer:

She spent around 20$

Step-by-step explanation:

add all whole numbers and estimate the cents.

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Answer:

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Step-by-step explanation:

Given that

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6 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
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Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

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3 years ago
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Answer:

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Step-by-step explanation:

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However, if you reverse it left-to-right, you get exactly the same figure. So, it has line symmetry about a vertical center line.

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