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Vladimir [108]
3 years ago
11

Daisy's teacher asked her class to draw a triangle whose sides measured 2 inches, 3 inches, and 4 inches. She correctly drew the

triangle below, and labeled the approximate angle measures.
image

Daisy's classmate, Bryan, drew a triangle with an angle that measured 35°. Could Bryan's triangle be correct as well?

A.
Yes, because there are many correct triangles with different angle measures.

B.
Yes, because the other correct triangle has an angle that measures 35°.

C.
No, because the other correct triangle does not have an angle that measures 35°.

D.
No, because there is only one unique correct triangle.
Mathematics
1 answer:
harina [27]3 years ago
4 0

Answer:

I dont think so since a triangle adds to 180 degrees

Step-by-step explanation:

but im stuck between c and d

sorry I couldnt complete;ly answer it for u!

have a nice day!

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3. The area of a square garden is 200 m? How long is the diagonal? (1 point)
zavuch27 [327]

Answer:

There should be 4 answers but pick the one closest to one side of the square.

Step-by-step explanation:

8 0
3 years ago
Simplify. 7x + 3(x - 2) - 4x + 8Simplify. 7x + 3(x - 2) - 4x + 8. A) 6x+2 B) 6x+14 C) 6x-2 D) 14x+2
Paladinen [302]

Answer:

A) 6x+2

Step-by-step explanation:

7x + 3(x - 2) - 4x + 8

Distribute the 3

7x + 3x - 6 - 4x + 8

Combine like terms

7x+3x-4x -6+8

6x +2

8 0
3 years ago
Read 2 more answers
Please help me answer this question ASAP! If you give me a stupid answer I will report your account
VladimirAG [237]

Answer:

B

Step-by-step explanation:

It is linear.

We can see the right side are multiples of 3. So the equation so the table is:

c = 3h

When h = 5   c = 15

c = 3h

c = 3*5

c = 15

When h = 12   c = 36

c = 3h

c = 3*12

c = 36

The constant rate of change between cost and time is 3.

Another way to solve is check for rate of change using 2 points on the chart.

Let's choose h = 5 c = 15      and h = 12 c = 36

The normal equation for rate of change is:

m = \frac{y_{2} -y_{1}}{x_{2}-x_{1}}  in this case we have h and c so:

\frac{c_{2} -c_{1}}{h_{2}-h_{1}}

h₁ = 5       h₂ = 12

c₁ = 15      c₂ = 36

So:

\frac{c_{2} -c_{1}}{h_{2}-h_{1}} = \frac{36 -15}{12-5} = \frac{21}{7} = \frac{3}{1} =3

Now that we know it's 3 we use slope intercept form to find the equation.

y = mx + b        ( m = 3) and we plug in a point to find b.

y = 3x + b          h = 5 (x)      c = 15 (y)

15 = 3(5) + b     Solve for b.

15 = 15 + b        Subtract 15 from each side.

15 - 15 = 15 - 15 + b

0 = b                 b is 0 showing our equation was correct.

y = 3x   or    c = 3h

6 0
3 years ago
Can someone tell me a easy way how to solve this problem ?
zlopas [31]
I believe its the first one because you can divide the H and pi which would be V/h×pi then you square root r2 and v/h×pi so r= square root of V/H×pi
6 0
3 years ago
In which number is the digit 2 one hundred times larger than it is in the number 524
Luda [366]

Answer: 2,504?

Step-by-step explanation: baccically times the 2 only by 100, or at least that’s what I am seeing. LOL

5 0
3 years ago
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