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alekssr [168]
4 years ago
15

Assume running consumes 103 calories per mile. If you run 9-minute mile, what is your average output in watts, during a 1-hour r

un?
Mathematics
1 answer:
Sergeu [11.5K]4 years ago
4 0
9 minutes ⇒ 1 mile
1 hour = 60 minutes
60 minutes ⇒ 60/9 mile = 6.667 miles

1 mile ⇒ 103 cal
6.667 miles ⇒ 6.667(103) cal = 686.667 cal

1 cal ⇒ 4.184 joules
686.667 cal ⇒ 2873.0133 joules

Watts = joules/time in seconds
60 minutes = 3600 seconds
<span>W = 2873.0133/3600 ≈ 0.79805925 <em>(round as needed)</em></span>
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x= -2 then y= 9

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The graph of the function decreases from left to right.

Option C is correct.

Step-by-step explanation:

We are given the function: y=(\frac{1}{3})^x

and we need to fill the table

if x = -3 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^-3

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^3 }\\y=\frac{1}{\frac{1}{27}}\\y=27

if x = -2 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^-2

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^2 }\\y=\frac{1}{\frac{1}{9}}\\y=9

if x = 2 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^2

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^2 }\\y=\frac{1}{9}

if x = 3 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^3

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^3 }\\y=\frac{1}{27}

So, x=-3 then y= 27

x= -2 then y= 9

x=2 then y: y=\frac{1}{9}

x=3 then y: y=\frac{1}{27}

Graph of the function is shown in figure attached.

The graph of the function decreases from left to right.

Option C is correct.

Keywords: Solving Equations

Learn more about Solving Equations at:

  • brainly.com/question/1563227
  • brainly.com/question/2403985
  • brainly.com/question/11229113

#learnwithBrainly

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