Hi, hope this helps :)
Feel free to ask me if you do not understand. I used the elimination method.
Answer:
<u>9 inches are 1/4 or 0.25 yards and we used inches in the numerator and yards in the denominator for our ratio.</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
1 yard = 36 inches
2. In converting 9 inches to yards, what unit (omit the number) would you place in the numerator of your ratio?
This is the ratio for calculating the answer:
36/1 = 9/x
36x = 9 *1
36x = 9
x = 9/36
x = 1/4 or 0.25 yards
<u>9 inches are 1/4 or 0.25 yards and we used inches in the numerator and yards in the denominator for our ratio.</u>
The initial height is 4
after 2 seconds, the height is 8
Brainliest answer, please?
Hi there! In this problem, you should have the knowledge of three basic Trigonometric Ratio.
- sinA = opposite/hypotenuse
- cosA = adjacent/hypotenuse
- tanA = opposite/adjacent
Now that we know three basic ratio. Let's check each choices!
This choice is wrong because we focus on the 50° angle. When we focus on 50°, sin50° should be d/x and not d/c.
This choice is also wrong because in ratio, it's cos50° that adjacent/hypotenuse.
This choice is correct! As ratio states, tanA = opposite/adjacent.
This choice is wrong. x/c is a reciprocal of cosine which is 1/cos. We call the reciprocal of cosine as secant or sec in short.
This choice is wrong as x/d is a reciprocal of sine which is 1/sin. We call the reciprocal of sine as cosecant or cosec/csc in short.
This choice is right by the ratio. Nothing really much to explain since we follow by ratio that is defined.
Answer
Questions can be asked through comment.
Furthermore, tan also has its reciprocal form itself which is called cotangent also known as cot in short.
Hope this helps, and Happy Learning! :)
Answer:
The answer is below
Step-by-step explanation:
Speed is the time rate of change of velocity, it is the ratio of distance to time.
Mr. Fowles runs at a steady 4.2 miles per hour. The time taken to cover 26 miles is:
speed = distance / time
time = distance / speed = 26 / 4.2 = 6.19 hour
I run at 3 miles per hour. I was given 3 mile lead, so the remaining distance is 23 miles (26 - 3). The time needed to complete the 23 miles is:
time = distance / speed = 23 / 3 = 7.67 hour
a) Let d be the distance Mr Fowles catches me. Hence:
time = (d + 3)/4.2; also time = d/3
(d + 3)/4.2 = d/3
3d + 9 = 4.2d
1.2d = 9
d = 7.5 miles
He would catch me at 10.5 (7.5 + 3) miles from the starting point.
b) Mr. fowles finishes after 6.19 hour. At that time, the distance is have covered is:
distance = 6.19 * 3 mi/hr = 18.57 mile
Distance behind = 23 mile - 18.57 = 4.43 mile
c) time longer = 7.67 hour - 6.19 hour = 1.48 hour