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alukav5142 [94]

3 years ago

15

The region below has a population of about 14,000 people. Select the best approximation for the population density of the region

.
5 mi

5 mi

100 people per square mile

180 people per square mile

350 people per square mile

500 people per square mile

1 answer:

Tcecarenko [31]3 years ago

5 0

180 people per square mile :)

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Find the product.Simplify your answer 1/-x*5y/-8

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1/-x*5y/-8
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find the Point of intersection of these 2 lines: y= 5x - 4 and y= 4x - 2 *write answer as (x,y) coordinate pair

harkovskaia [24]

The point of intersection is (2,6).

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4 years ago

A line with a slope of -2 passes through the points (0,d) and (-8,9). What is the value of d?

Verizon [17]

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have m = -2 and the points (0, d) and (-8, 9). Substitute:

$\dfrac{9-d}{-8-0}=-2\\\\\dfrac{9-d}{-8}=-2\qquad\text{multiply both sides by (-8)}\\\\9-d=16\qquad\text{subtract 9 from both sides}\\\\-d=7\qquad\text{change the signs}\\\\\boxed{d=-7}$

4 0

4 years ago

B is the midpoint of AC, E is the midpoint of BD. If A(-9,-4), C(-1,6), and E(-4,-3), find the coordinates of D

Vadim26 [7]

Answer:

(-3, -7)

Step-by-step explanation:

Let $(x_{A,}y_{A}),(x_{B},y_{B}),(x_{C,}y_{C}),(x_{D,}y_{D})(x_{E,}y_{E)} \text{be the coordinates of points A, B, C respectively}\\\\$

The midpoint coordinates $(x_{M},y_{M})$ of any two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ are given by $x_{M}=\frac{(x_{1}+x_{2)}}{2}$ and $y_{M}=\frac{y_{1}+y_{2}}{2}$

Since B is the midpoint of AC

$x_{B}=\frac{(x_{A}+x_{C})}{2}=\frac{(-9+(-1)}{2}=\frac{-9-1}{2}=\frac{-10}{2}=-5$

$y_{B}=\frac{(y_{A}+y_{C})}{2}=\frac{(-4+6)}{2}=\frac{2}{2}=1$

Since E is the midpoint of B and D and we are given the coordinates of E as (-4,-3). it follows that

$x_{E}=\frac{x_{B}+x_{D}}{2} = \frac{-4+x_{D}}{2}$

Therefore

$x_{D}=2x_{E}+4=2(-5)+4=-3$

Similarly

$y_{E}=\frac{y_{B}+y_{D}}{2} = \frac{1+x_{D}}{2}y_{D}=2y_{E}-1=2(-3)-7=-7$

8 0

2 years ago