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Anarel [89]
3 years ago
8

Can someone please help me solve this and find the answer? Thanks so much!

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
5 0
Your answer is 8.626
Because it's a square, you know that each side is 8 because √64 = 8. This also tells you that the radius of each of the outer circles is 4.
Because each side of the square is 8, you can use Pythagoras' Theorem to find the diagonal, and do 8² + 8² = 64 + 64 = 128, so √128 is the diagonal (I'm leaving it in surd form because it's a pretty long number). You first need to divide √128 by 2, because you're trying to find the radius of circle O, so that gives you 5.657.
Because you know that the radius of the outer circle is 4, you can subtract 4 from this and get 1.657 as your radius. Now, we can use this to find the area of the circle by doing π × 1.657² = 8.626.

I hope this helps!
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Newton's Law of Cooling states that the rate of change of the temperature of an object, T, is proportional to the difference of
maria [59]

Answer:

  305 °F

Step-by-step explanation:

The core temperature of the object after 4 hours can be found using an exponential decay formula to model the decay of the difference between core temperature and ambient.

<h3>Cooling Model</h3>

The solution to the differential equation described by Newton's law of cooling is the exponential equation ...

  y = ab^t +c

where 'a' is the initial core temperature difference from ambient, 'b' is the decay factor of that difference in 1 unit of time period t. 'c' is the ambient temperature.

For this problem, the ambient temperature is c=80, and the differences of interest are ...

  a = 1200 -80 = 1120

  b = (830 -80)/1120 = 75/112

Using these values in the model gives ...

  y = 1120(75/112)^t +80 . . . . . . where y(t) is the core temperature at time t

Note that units of time are hours.

<h3>Application</h3>

We want y when t=4.

  y = 1120(75/112)^4 +80 ≈ 1120(0.20108) +80 ≈ 305.212

The core temperature after 4 hours is about 305 °F.

__

<em>Additional comment</em>

The differential equation will have a solution of the form ...

  T-T_R=(T_0-T_R)e^{kt}

where k = ln(75/112) ≈ -0.40101

In the above, we defined b = e^k = 75/112. Accuracy with this fraction can be better than using a truncated value of k.

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2 years ago
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___
x = 20
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∠C = 40°
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