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Anna007 [38]
3 years ago
9

A high-speed drill rotating counterclockwise takes 2.5 s to speed up to 2400 rpm. (a) What is the drill’s angular acceleration?

Physics
1 answer:
defon3 years ago
8 0

Answer:

(a) Angular acceleration will be 100.53rad/sec^2

(b) 50 revolution

Explanation:

We have given time t = 2.5 sec

Initial speed of the drill \omega _0=0rad/sec

Speed after 2.5 sec =2400rpm=\frac{2\pi \times 2400}{60}=251.327rad/sec

From first equation of motion we know that

\omega =\omega _0+\alpha t

251.327 =0+\alpha \times 2.5

\alpha =100.53rad/sec^2

(b) From second equation of motion we know that

\Theta =\omega _0t+\frac{1}{2}\alpha t^2

\Theta =0\times 2.5+\frac{1}{2}\times 100.53\times  2.5^2=314.16rad=\frac{314.16}{2\pi }=50revolution

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