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Ad libitum [116K]
3 years ago
15

The three main phases of matter (not including plasma) are solids, liquids, and gases. They have different properties concerning

the arrangement of particles. Choose all of the statements that are true.
Physics
2 answers:
Reil [10]3 years ago
7 0

Answer:

The statements to choose from are not shown in your question, but find below some characteristics of these three main phases, which may help you choose the right answers you are seeking.

Explanation:

Solid: The matter that constitutes it maintains a fixed volume and shape, with the particles that compose it close together and relatively fixed into place.

Liquid: The matter that constitutes it maintains a fixed volume, but has a variable shape that adapts to fit its container. Its particles are still close together but move freely.

Gas: The matter that constitutes it has both variable volume and shape, adapting both to fit its container. Its particles are neither close together nor fixed in place.

Vladimir79 [104]3 years ago
6 0

Answer:

solids have the most tightly-packed particle arrangement

liquids are closely-packed but with no regular arrangement

gases are loosely-packed and have no regular arrangement

Explanation:

usatestrep

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Velocity = 2.47 m/s

The answer is D) 2.47 m/s at 61.9 degrees

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Is the velocity used to calculate reynolds number, average velocity?
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Two ladders of uniform density and equal mass m are propped up against
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4 years ago
A rope is wrapped around a pulley many times. The pulley can be modeled as a solid disk of radius R and mass M, and a mass mA ha
aleksandr82 [10.1K]

The magnitude of the tangential acceleration of the hanging mass is 2mg/MR

<h3>Tangential acceleration of the hanging mass</h3>

The tangential acceleration of the hanging mass around the pulley is determined from the principle of conservation of angular momentum as shown below;

τ = Iα

Where;

  • I is the moment of inertia
  • α is the angular velocity

\alpha = \frac{\tau}{I} \\\\\alpha = \frac{mgR}{3/2MR^2} \\\\\alpha = \frac{2mgR}{3MR^2} \\\\\alpha = \frac{2mg}{3MR}

Where;

  • m is the hanging mass
  • M is the mass of solid disk

The tangential acceleration is calculated as follows;

a = \alpha R\\\\a = \frac{2mg}{3MR} \times R\\\\a = \frac{2mg}{3M}

Thus, the magnitude of the tangential acceleration of the hanging mass is 2mg/MR

Learn more about tangential acceleration here: brainly.com/question/11476496

4 0
3 years ago
A U-tube is open to the atmosphere at both ends. Water is poured into the tube until the water column on the vertical sides of t
zmey [24]

Answer:

The value is  \Delta h  =  0.003 \  m

Explanation:

From the question we are told that

   The  height of the water is  h_1  =  10 \ cm  =  0.10 \  m

    The  density of  oil is \rho_o  =  950 \  kg/m^3

  The  height of  oil  is  h_2  =  6 \ cm  =  0.06 \  m

Given that both arms of the tube are open then the pressure on both side is the same

So  

      P_a =  P_b

=>   Here  

             P_a  =  P_z + \rho_w  *  g *  h

where  \rho_w is the density of water with value  \rho_w =  1000 \ kg/m^3

and  P_z is the atmospheric pressure

and  

        P_b  =  P_z + \rho_o  *  g *  h_2

=>   P_z + \rho_w  *  g * h =    P_z + \rho_o  *  g *  h_2

=>    \rho_w   * h  =    \rho_o  *  h_2

=>      h  =  \frac{950 * 0.06 }{1000}

=>      h  = 0.057 \ m

The  difference in height is evaluated as    

           \Delta h  =  0.06 - 0.057

          \Delta h  =  0.003 \  m

     

6 0
4 years ago
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