Answer:
a=2.378 m/s^2
Explanation:
a=Δv/Δt------eq(1)
Δv=Vf-Vi=120 km/h-0 km/h=120 km/h
or Δv=33.3 m/sec
or time=t=14s
putting values in eq(1)
a=33.3/14
a=2.378 m/s^2
Answer:
A λ = 97.23 nm
, B) λ = 486.2 nm
, C) λ = 53326 nm
Explanation:
With that problem let's use the Bohr model equation for the hydrogen atom
= -k e² /2a₀ 1/n²
For a transition between two states we have
- = -k e² /2a₀ (1/ ² - 1 / n₀²)
Now this energy is given by the Planck equation
E = h f
And the speed of light is
c = λ f
Let's replace
h c / λ = - k e² /2a₀ (1 / ² - 1 / no₀²)
1 / λ = - k e² /2a₀ hc (1 / ² -1 / n₀²)
Where the constants are the Rydberg constant = 1.097 10⁷ m⁻¹
1 / λ = (1 / n₀² - 1 / nf²)
Now we can substitute the given values
Part A
Initial state n₀ = 1 to the final state = 4
1 / λ = 1.097 10⁷ (1/1 - 1/4²)
1 / λ = 1.0284 10⁷ m⁻¹
λ = 9.723 10⁻⁸ m
We reduce to nm
λ = 9.723 10⁻⁸ m (10⁹ nm / 1m)
λ = 97.23 nm
Part B
Initial state n₀ = 2 final state = 4
1 / λ = 1.097 10⁷ (1/2² - 1/4²)
1 / λ = 0.2056 10⁻⁷ m
λ = 486.2 nm
Part C
Initial state n₀ = 3
1 / λ = 1,097 10⁷ (1/3² - 1/4²)
1 / λ = 5.3326 10⁵ m⁻¹
λ = 5.3326 10-5 m
λ = 53326 nm
Since in an electromagnetic wave the electric and magnetic fields are perpendicular to each other and perpendicular to the direction of motion, the electric field has to point in the z direction.
They are called lubricants.
Answer:
Vy = 0
y(max) = 137,76 m
x(max) = 318 m
Explanation:
We are dealing with a projectile movement
And from problem statement we know:
θ = 60⁰ then sin θ = sin 60⁰ = √3/2 and cos 60⁰ = 1/2 and g = 9.8 m/sec²
V₀ = 60 m/sec
V₀x = V₀ *cosθ Vx = V₀x Vx = Constant then Vx = V₀ *cosθ
Then Vx = 60* 1/2 Vx = 30 m/sec
V₀y = V₀ *sinθ ⇒ V₀y =60*√3/2 ⇒ V₀y = = 30*√3 m/sec
Vy = V₀y * sin θ - g*t
When Vy = 0 (maximum height point) we are half of the way for the ball to hit the ground, then
Vy = 0 ⇒ V₀y - g*t = 0 ⇒ 30*√3 (m /sec) = 9,8 (m/sec²)* t
t = 30*√3/9.8 t = 5.30 sec
y(max) = y₀ + V₀y*t - 1/2 * g*t²
By substitution:
y (max) = 0 + 30*√3 * 5.30 - 0,5* 9.8* (5.3)²
y(max) = 275,40 - 137,64
y(max) = 137,76 m
And finally x(max)
x(max) = Vx *t = 30* 2*5,3
x(max) = 318 m