Ask question

Ask question

All categories

3 years ago

5

Why don't the two forces in Newton's third law cancel each other? They act in the same direction. They are different kinds of fo

rces. They have different magnitudes. They act on two different objects. They act in different directions.

1 answer:

pogonyaev3 years ago

5 0

Answer:They act on different bodies

Explanation:

Newton's third law of motion states that for every action there is equal and opposite reaction i.e. action and reaction. Though action and reaction are equal they act in different bodies that is why they do not cancel out each other.

For example, a block of mass m placed over the table exerts a force of mg to the table while the table applies a Normal reaction of equal magnitude as of mg to the block of mass m.

You might be interested in

A block is balanced on top of a frictionless sphere of radius R. When the block is given a slight nudge it starts to slide down

Nataly_w [17]

Answer: $\frac{R}{3}$

Explanation:

Given

Sphere of Radius R

Suppose mass of block is m

At any instant \theta Normal reaction(N) and weight(mg) is acting such that

$mg\sin \theta -N=\frac{mv^2}{R}$ , where v is velocity of block at any angle \theta

When block is just about to leave then N=0

therefore

$mg\sin \theta =\frac{mv^2}{R}$

$v^2=gR\sin \theta$ -------------------1

Also by conserving Energy we get

Potential Energy=kinetic Energy of block

$mgh=\frac{mv^2}{2}$

here h=vertical distance traveled by block

From diagram

$h=R-R\sin \theta$

$h=R(1-\sin \theta )$

$mgR(1-\sin \theta )=\frac{mv^2}{2}$

$2gR(1-\sin \theta )=v^2$ -----------------2

From 1 and 2

$2(1-\sin \theta )=\sin \theta$

$3\sin \theta =2$

$\sin \theta =\frac{2}{3}$

Thus from this value of h is

$h=R(1-\sin \theta )$

$h=R(1-\frac{2}{3})$

$h=\frac{R}{3}$

3 0

4 years ago

A golf club exerts an average horizontal force of 1000 n on a 0.045 -kg golf ball that is initially at rest on the tee. the club

OlgaM077 [116]

The impulse (the variation of momentum of the ball) is related to the force applied by
$\Delta p = F \Delta t$
where $\Delta p$ is the variation of momentum, F is the intensity of the force and $\Delta t$ is the time of application of the force.
Using F=1000 N and $\Delta t = 1.8 ms=1.8 \cdot 10^{-3}s$ , we can find the variation of momentum:
$\Delta p = (1000 N)(1.8 \cdot 10^{-3} s)=1.8 kg m/s$

This $\Delta p$ can be rewritten as
$\Delta p = p_f - p_i = mv_f - mv_i$
where $p_f$ and $p_i$ are the final and initial momentum. But the ball is initially at rest, so the initial momentum is zero, and
$\Delta p = mv_f$
from which we find the final velocity of the ball:
$v_f = \frac{\Delta p }{m}= \frac{1.8 kg m/s}{0.045 kg}= 40 m/s$

8 0

3 years ago

What is the Isotope notation for a Lithium atom?

Serggg [28]

Lithium has five isotopes, and each will have different notation. Lithium-7 is commonly used in salt and nuclear reactors. .ZAX , where X is the atomic symbol for the element, here Li for lithium, Z is the mass number, or the total number of protons and neutrons, and A is the atomic number, or the number of protons

6 0

3 years ago

A metal rod of length 2.0 m is moved at 6.0 m/s in a direction perpendicular to its length. A 5.0 mT magnetic field is perpendic

Lerok [7]

Answer:

<h2>The potential difference is 60mV</h2>

Explanation:

This problem bothers on application of the expression for motion emf which is expressed as

$E= Blv$

where B= magnetic field in Tesla

l= length of the conductor

v= speed of conductor

Given data

l= 2 meters

v= 6 m/s

B= 5 Tesla

Applying the formula we have

$E=5*2*6= 60mV$

7 0

3 years ago

Which state of matter is most similar to solids

STatiana [176]

Answer:

liquids in pretty sure

7 0

3 years ago

Read 2 more answers