6 )532 with a Remainder

Cole says that all quadrilaterals are polygons but not all polygons are quadrilaterals is he correct explain��

zepelin [54]

YES, this is correct. All quadrilaterals whether is a trapezoid, parallelogram, rhombus and others, they are all polygons and all they have 4 sides and 4 angles. We know that a polygon is a figure with at least three sides and three angles.

Not all polygons are quadrilateral, this is also correct since some polygons have five or more sides and angles.

7 0

3 years ago

In a test (+5) marks are given for every correct answer and (-2) marks are given for every incorrect answer. Smitha answered all

Ymorist [56]

Answer:

15 answers

Step-by-step explanation:

To solve this question we need to set up an equation.

Let's name the number of incorrect answers x.

We can set up an equation that's essentially:

(Points for correct answer)*(number of correct answers)+(points for incorrect answer)*(number of incorrect answers)=final score

When we plug in our numbers and variables it looks like this:

5(3)+(-2x)=-15

Simplify

15-2x=-15

Subtract 15 from both sides

-2x=-30

Divide both sides by -2

x=15

This means Smitha attempted 15 wrong answers, and that there were 18 questions in total.

6 0

2 years ago

According to a study done by Wakefield Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

UNO [17]

Answer:

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

Step-by-step explanation:

We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.

Let $\hat p$ = sample proportion of Americans who can order a meal in a foreign language

The z-score probability distribution for sample proportion is given by;

Z = $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion

p = population proportion of Americans who can order a meal in a foreign language = 0.47

n = sample of Americans = 200

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( $\hat p$ > 0.50)

P( $\hat p$ > 0.06) = P( $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ > $\frac{0.5-0.47}{\sqrt{\frac{0.5(1-0.5)}{200} } }$ ) = P(Z > 0.85) = 1 - P(Z $\leq$ 0.85)

= 1 - 0.80234 = 0.19766

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.

Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

4 0

4 years ago

3 1/25 into a decimal

babunello [35]

Answer:

3.04

Step-by-step explanation:

4 0

4 years ago

Reuben and Susan each opened a savings account today. Reuben opened his account with a starting amount of 320, and he is going t

navik [9.2K]

X represents the amount of money added in

320+85x=820+35x

3 0

2 years ago