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Svet_ta [14]
4 years ago
9

A scatter plot is shown below.. PLEASE HELPPP!!

Mathematics
2 answers:
AnnyKZ [126]4 years ago
8 0

Answer:

(0,9.8) and (10, 1.2)

Step-by-step explanation:

These are the only points that are the best fit for the garph correlation.

Allisa [31]4 years ago
7 0

Answer:

(0, 9.8) and (10, 1.2)

Step-by-step explanation:

:) hope this helped

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Is the equation linear or quadratic?<br> t(x)=x+5<br> O A. linear<br> O B. quadratic
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Answer:

A. Linear

Step-by-step explanation:

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4 0
3 years ago
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Compare the functions shown below:
insens350 [35]
<span>The function f(x) = x^3 + 2x^2 - 4x - 3 is a polynomial function of degree 3 and hence will have three solutions and hence 3 x-intercepts. The function g(x) has x-intercepts at x = -2, x = -1, x = 1 and x = 3. Hence function g(x) has 4 x-intercepts. The function h(x) has x-intercepts at points (pi over 2, 0) and (3 pi over 2, 0). Hence function h(x) has 2 x-intercepts. Therefore, the function with the most x-intercepts is function g(x) with 4 x-intercepts.</span>
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3 years ago
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At the beginning of year 1, Bode invests $250 at an annual simple interest rate of 3%. He makes no deposits to or withdrawals fr
Dennis_Churaev [7]
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250

At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5

So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50 </span>
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4 years ago
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