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sergey [27]
3 years ago
12

How do I solve: "1/6y-4= -7"?

Mathematics
1 answer:
Shtirlitz [24]3 years ago
7 0
1/6y - 4 = -7

1/6y = -7 + 4

1/6y = -3

1 = -18y

 -18y = 1

answer
y = -1/18 
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rosijanka [135]
The slope is 9/1 hope i helped
8 0
3 years ago
Write the relation as a set of on rdered pai
kirill115 [55]

The relation as a set of ordered pairs is d. {(–2, 1), (0, -1), (2, -3)}.

Step-by-step explanation:

Step 1:

First, we plot the three points on the given graph.

The coordinates are given in the following form (x coordinate, y coordinate) where the symbol of the coordinates depends on the quadrant on which the point lies.

For the first quadrant, both x and y values are positive.

For the second quadrant, the x value is negative but the y value is positive.

For the third quadrant, both the values of x and y are negative.

For the fourth quadrant, the x value is positive but the y value is negative.

Step 2:

The first point has an x value of 2 and a y value of 1 since it is in the second quadrant, the coordinates are (-2, 1).

The second point has an x value of 0 and a y value of 1 since it is in the third or fourth quadrant, the coordinates are (0, -1).

The third point has an x value of 2 and a y value of 3 since it is in the fourth quadrant, the coordinates are (2, -3).

So the coordinates are {(–2, 1), (0, -1), (2, -3)} which is option d.

6 0
3 years ago
Https://brainly.com/question/20878483
snow_tiger [21]

Answer:

Oh okayy

Step-by-step explanation:

3 0
3 years ago
A spool of rope contains 67 yards of rope. How many​ 4-foot pieces of rope can be cut from the​ spool? How much rope is left​ ov
ehidna [41]

Answer:

50 pieces with 3 inches left

Step-by-step explanation:

67*3 = 201

201/4 = 50.25

.25 * 12 = 3 inches

6 0
3 years ago
What are the restrictions for a? 2a^2+a-15/5a^2+16a+3
koban [17]

ANSWER


The restrictions are

a\ne -3,a\ne -\frac{1}{5}


EXPLANATION


We were given the rational function,


\frac{2a^2+a-15}{5a^2+16a+3}


The function is defined for all values of a, except



5a^2+16a+3=0


This has become a quadratic trinomial, so we need to split the middle term.


We do that by multiplying the coefficient of x^2 which is 5 by the constant term which is 3. This gives us 15.


The factors of 15 that adds up to 16 are 1 and 15.


We use these factors to split the middle term.




5a^2+15a+a+3=0


We now factor to get,


5a(a+3)+1(a+3)=0


We factor further to get,


(a+3)(5a+1)=0



This implies that,


(a+3)=0,(5a+1)=0


This gives


a=-3,a=-\frac{1}{5}


These are the restrictions.





8 0
3 years ago
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