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nalin [4]
3 years ago
11

3. Kevin and Hannah are both saving money for a new television. Kevin has already saved $ 47 and

Mathematics
1 answer:
alexira [117]3 years ago
5 0

Answer:

47+16w=

20+25w=

Step-by-step explanation:

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PLEASE HELP!! i cant figure out how to do it
vodomira [7]

Answer:

168 and 12

Step-by-step explanation:

use fractions for this think of it as 14/15x and 1/15x and x is 180 and solve from there

3 0
2 years ago
Tony has 60$ to buy souvenirs for his grandkids at the baseball game. Pennants cost $7.50 and hats cost $11.99. This relationshi
Step2247 [10]
C. 0<p<3 is the answer (at most) 

Hope dis helped :)
4 0
3 years ago
Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
Length of a rectangle is four times its width. If the perimeter is 100 m, what is the area in square cm?
melisa1 [442]

Set the width to be x. Thus, the length is 4x.

The perimeter is 2(x+4x)=100, so x=10.

Plugging in x=10, you get that 4x=40.

So, the area of the rectangle is 400 m^2.

Because there are 100 centimeters in a meter and you are asking for area, you must multiply by 100^2 to get 4000000 cm^2.


6 0
3 years ago
The movie theater sold 50 buckets of popcorn last Wednesday. 60 people watched movies that day, and 40 of those people ate popco
STALIN [3.7K]

Answer:

70

Step-by-step explanation:

60/40Ⅹ50=70

I hope this helps

3 0
2 years ago
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