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melamori03 [73]
3 years ago
14

Two objects, object X and Object Y, are held together by a light string

Physics
1 answer:
Vinil7 [7]3 years ago
7 0

Answer:

This question is incomplete

Explanation:

The completed question is in the attachment to this question

The two objects (X and Y) at rest had a potential energy of Mx.gH and My.gH respectively because the formula for potential energy (P.E) is mgh. Where m is the mass of the object, g is acceleration due to gravity and h is the height of the object above the ground. Hence, Mx and My are the masses of X and Y respectively.

The change in there potential energy to kinetic energy and back to there potential energy will be

P.E of Y - P.E of X (because mass of Y is larger and will hit the floor first)

Hence, My.gH - Mx.gH ⇔ (My - Mx)gH

Correct option is C

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Leona [35]
<h2>Question no. 1: </h2><h3>Answer: </h3>

Controlled experiment is an experiment which is designed to test a variable, which can be changed during the experiment.

<h3>Explanation: </h3>

Hence in this experiment, the importance of experiment is being tested, as it is added only in one set of plant.

A manipulated variable is an independent variable whose amount can be changed during an experiment.

Here the fertilizer is a manipulated variable.

<h2>Question 2: </h2><h3>Answer: </h3>

Because theory is the most organised statement proved by a set of independent experiments.

<h3>Explanation: </h3>

Hypothesis is the initial idea on which basis different experiments are conducted. But if 1 experiment succeeded and it supports the hypothesis, hypothesis do not become a theory.

For a theory, different experiments are necessary which supports that hypothesis.

<h2>Question no 4. </h2><h3>Answer: </h3>

Density = 1.909 kg/m3

<h2>Explanation: </h2>

Given data:

Mass of the object = 42 kg

Volume of the object = 22 m3

Density of the object = ?

Solution

Density = mass/volume

Density =42/22 = 1.909

Density = 1.909 kg/m3

<u><em>Hence the density of the object is 1.909 and its unit is kg/m3 which is system international unit of density. </em></u>

<h2>Question 5. </h2><h3>Answer: </h3>

Chlorine and water in swimming pool are mixed in such a way that there composition remains same throughout the mixture. And chlorine cannot be separated back from water. This is the homogeneous mixture.

<h3>Explanation: </h3>
  • A homogeneous mixture is a mixture of more than one substance which are mixed together in such a way that they cannot be separated and the composition of the mixture remains same throughout the mixture.
  • Example of homogeneous solution is sugar solution in water.
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<h2>Question no. 6. </h2><h3>Answer: </h3>

Because physical change does not include composition change, it includes change in physical parameters. And in splicing tomato only change in shape is done.

<h3>Explanation: </h3>
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Remaining questions are attached in the files.

<h2 />
Download pdf
3 0
3 years ago
A load of 500N is carried by 200N effort in a simple machine having load distance 3m Calculate effort distance.​
vlada-n [284]

Answer:

<h2>2.5 m</h2>

Explanation:

Load ( L ) = 500 N

Effort ( E ) = 200 N

Load distance ( LD ) = 3 m

Effort distance ( ED ) = ?

Now, Let's find the Effort distance ( ED )

We know that,

Output work = Input work

i.e L × LD = E × ED

plug the values

500 \times 3 = 200 \times ED

multiply the numbers

1500 = 200 \times ED

Swipe the sides of the equation

200 \: ED \:  = 500

Divide both sides of the equation by 200

\frac{200 \: ED}{200}  =  \frac{500}{200}

Calculate

ED\:  = 2.5 \: m

Hope this helps..

best regards!!

5 0
3 years ago
An 8-inch dinner knife is sitting on a circular plate so that its ends are on the edge of the plate. if the minor arc that is in
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When we form a right triangle connecting the edge of the knife to the center of the circle and the center of the knife to the center of the circle, the radius of the circle becomes the hypotenuse. Using the trigonometric function,
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4 years ago
What are the characteristics of high energy wave lengths
Darya [45]
The characteristics of high energy wave length are:
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3 0
4 years ago
If you know the amount of air pressure exerted on a tabletop, how can you calculate the force exerted on the tabletop? Multiply
babymother [125]

Answer:

Multiply the air pressure by the area of the tabletop.

Explanation:

The relationship between pressure, force and area is given by:

p=\frac{F}{A}

where in this case, p is the air pressure, F is the force exerted and A the area of the tabletop. By re-arranging the equation, we can solve for F, the force exerted:

p=\frac{F}{A}\\p\cdot A=\frac{F}{A}\cdot A\\pA=F

So, the correct answer is:

The force exerted on the tabletop can be found by multiplying the air pressure by the area of the tabletop.

7 0
4 years ago
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