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ollegr [7]
3 years ago
7

Explain why conductors and insulators are both required to construct the electrical wiring in your home

Physics
1 answer:
hoa [83]3 years ago
8 0
Conductors (something that allows electricity to flow easily) allow for electricity to flow easily. This would be the wires. If you don't have conductors, then you cannot have electricity flow.

Insulators (something that doesn't allow electricity to flow through it) is important because it allows us to be able to touch the cables or place them next to one another and not shock ourselves.
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A hockey puck sliding at 60.0m/s slows uniformly to 20.0m/s while travelling 800.0m.
julia-pushkina [17]
A) -3.75 meters/second
A=(20^2-80^2)/(2x800)
=(400-6400)/1600
=-6000/1600
=-3.75
B) 16 seconds
t=(20-80)/-3.75
=-60/-3.75
=16
3 0
3 years ago
A traveler pulls on a suitcase strap at an angle 36 above the horizontal with a force of friction of 8 N with the floor. If 752
goldenfox [79]

Answer:

71.8 N

Explanation:

T = Tension force in the strap

W = net work done = 752 J

f = force of friction = 8 N

d = displacement = 15 m

θ = angle between tension force and horizontal displacement = 36 deg

work done by frictional force is given as

W' = - f d

Work done by the tension force is given as

W'' = T d Cos36

Net work done is given as

W = W' + W''

W = T d Cos36 - f d

752 = T (15) Cos36 - (8) (15)

T = 71.8 N

8 0
3 years ago
What is Sir Isaac Newton most commonly known for?
Ede4ka [16]

Answer:

Isaac Newton is best known for having invented the calculus

Explanation:

6 0
3 years ago
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Which scientist continued the work of another while studying the elliptical path of planets? Name both scientists. Kepler advanc
Korolek [52]
This question is so vague as to render it useless.

I suspect the answer they're looking for is Kepler advanced Copernicus's work as is stated. but the way science works is that anyone who has contributed will have their work built on. for example, Newton advanced Kepler's work on the elliptical path of planets as Einstein advanced Newton's work.
3 0
4 years ago
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A wire has a current density of 6.25 × 10 6 A / m 2 6.25×106 A/m2 . If the cross-sectional area of the wire is 1.79 mm 2 1.79 mm
joja [24]

Answer:17.44A

Explanation: Current density=I/Area

Area is given by 2.79mm^2=2.79×10^-6m^2

Current=I=current density ×Area=6.25×10^6 ×2.79×10^-6=17.44A

3 0
3 years ago
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