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alukav5142 [94]
3 years ago
12

3. A dog walks a distance of 100 ft. in 20 s of time. What is the dog's

Physics
2 answers:
natta225 [31]3 years ago
8 0
The answer is A.
100/20=5
ICE Princess25 [194]3 years ago
7 0
A trust I have done this question
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10. when creating a cardiovascular fitness routine which program would be appropriate?
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10. B

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14. B, any type of stretching is good before you perform any type of physical activity because it loosens up the muscles

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Explanation:

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Can you explain the three main important reason why we use machine​
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HERE IS YOUR ANSWER

Explanation:

1. The machines makes pur life easier.

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How do I draw a four-cell battery with the cells connected in series with each other?
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2 years ago
Point charges q1 = 14 µC and q2 = −60 µC are fixed at r1 = (5.0î − 4.0ĵ) m and r2 = (9.0î + 7.5ĵ) m. What is the force (in N) of
Lostsunrise [7]

Answer:

The force on q₁ due to q₂ is (0.00973i + 0.02798j) N

Explanation:

F₂₁ = \frac{K|q_1|q_2|}{r^2}.\frac{r_2_1}{|r_2_1|}

Where;

F₂₁ is the vector force on q₁ due to q₂

K is the coulomb's constant = 8.99 X 10⁹ Nm²/C²

r₂₁ is the unit vector

|r₂₁| is the magnitude of the unit vector

|q₁| is the absolute charge on point charge one

|q₂| is the absolute charge on point charge two

r₂₁ = [(9-5)i +(7.4-(-4))j] = (4i + 11.5j)

|r₂₁| = \sqrt{(4^2)+(11.5^2)} = \sqrt{148.25}

(|r₂₁|)² = 148.25

F_2_1=\frac{K|q_1|q_2|}{r^2}.\frac{r_2_1}{|r_2_1|} = \frac{8.99X10^9(14X10^{-6})(60X10^{-6})}{148.25}.\frac{(4i + 11.5j)}{\sqrt{148.25} }

      = 0.050938(0.19107i + 0.54933j) N

      = (0.00973i + 0.02798j) N

Therefore, the force on q₁ due to q₂ is (0.00973i + 0.02798j) N

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3 years ago
If the refractive index of a medium is 1.3,
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