I believe The snowman should be the answer
Suppose the stone is thrown at an angle of 39.0° below the horizontal from the same building as in the Example above. If it strikes the ground 47.8 m away, find the following. (Hint: For part (a), use the equation for the x-displacement to eliminate v0t from the equation for the y-displacement.)(a) the time of flight sThe x coordinate as a function of time is x(t) = vcos(39.0)t, so the initial speed is v0 = Δx/(cos 39.0Δt), where Δx = 47.8 and Δt is the time of flight. Insert this into your equation for y(t) and solve for the time of flight. Note that the answer should be smaller than 3.16227766016838, since the stone is thrown down (and to the right).(b) the initial speed m/s(c) the speed and angle of the velocity vector with respect to the horizontal at impactspeed m/sangle °
Answer:
1
![t_a = 13.49 \ s](https://tex.z-dn.net/?f=%20t_a%20%20%3D%20%2013.49%20%5C%20%20s%20%20%20)
2
The distance is
Explanation:
From the question we are told that
The maximum speed of the cheetah is ![v = 103 \ km/h = 28.61 \ m/s](https://tex.z-dn.net/?f=v%20%3D%20%20103%20%5C%20%20km%2Fh%20%3D%20%2028.61%20%5C%20%20m%2Fs)
The maximum of gazelle is ![u = 76.5 \ km/h = 21.25 \ m/s](https://tex.z-dn.net/?f=u%20%3D%20%2076.5%20%5C%20%20km%2Fh%20%3D%20%2021.25%20%5C%20%20m%2Fs)
The distance ahead is ![d = 99.3 \ m](https://tex.z-dn.net/?f=d%20%3D%20%2099.3%20%5C%20%20m)
Let
denote the time which the cheetah catches the gazelle
Gnerally the equation representing the distance the cheetah needs to move in order to catch the gazelle is
![v* t_a = d + u* t_a](https://tex.z-dn.net/?f=%20v%2A%20t_a%20%3D%20d%20%2B%20%20u%2A%20t_a%20)
=> ![28.61 t_a = 99.3 + 21.25t_a](https://tex.z-dn.net/?f=%2028.61%20t_a%20%3D%2099.3%20%2B%20%2021.25t_a%20)
=> ![7.36 t_a = 99.3](https://tex.z-dn.net/?f=%207.36%20t_a%20%3D%2099.3%20%20)
=> ![t_a = 13.49 \ s](https://tex.z-dn.net/?f=%20t_a%20%20%3D%20%2013.49%20%5C%20%20s%20%20%20)
Now at t = 7.5 s
![7.5 v = D+ 7.5u](https://tex.z-dn.net/?f=7.5%20v%20%3D%20D%2B%20%207.5u%20)
=> ![28.61 * 7.5 = D + 21.25* 7.5](https://tex.z-dn.net/?f=%2028.61%20%2A%207.5%20%20%3D%20D%20%2B%20%2021.25%2A%207.5%20%20)
=> ![7.36 * 7.5 =D](https://tex.z-dn.net/?f=%207.36%20%2A%20%207.5%20%3DD%20%20)
=>
Hence the for the gazelle to escape the cheetah it must be 55.2 m
Answer:
16.96 W
Explanation:
Power: This can be defined as the rate at which work is done by an object. The S.I unit of power is Watt(W).
From the question,
P = (F×d)/t....................... Equation 1
Where P = power, F = force, d = distance, t = time.
Given: F = 75 N, d = 42 m, t = 3.1 min = 3.1×60 = 186 s
Substitute these values into equation 1
P = (75×42)/186
P = 16.94 W
Hence the average power delivered by the child = 16.96 W