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klio [65]
3 years ago
13

A 50.0-g Super Ball traveling at 25.0 m/s bounces off a brick wall and rebounds at 22.0 m/s. A

Physics
1 answer:
Setler [38]3 years ago
7 0

Explanation:

Average acceleration is change in velocity over time.

a = Δv / Δt

a = (22.0 m/s − (-25.0 m/s)) / 0.00350 s

a = 13,400 m/s²

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What do women and men prefer in partners?
hodyreva [135]

Answer:

I would say Honesty, Loyalty, and Trust

Explanation:

well, thats just in my opinion and other people have their own preferences

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An object falling from a great height in Earth's atmosphere eventually reaches a speed called Terminal velocity. What cause a fa
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Answer:

A.

Explanation:

If its at a height the Gratitude of it falling down with only Gravity if Any other Forces are acting on it so as Friction But Sideways.

5 0
3 years ago
Which order shows increasing energy of photons?
Alchen [17]

The correct answer is C. microwaves, infrared, visible, gamma rays

Electromagnetic waves arranged in order of  frequencies and wavelengths form the electromagnetic spectrum. In the order of decreasing frequency we obtain the following sequence.

Gamma ray>x-ray>ultraviolet >visible light>infrared light>microwaves>radio waves.

According to the Einsteins equation, E=hf, Energy is  directly proportional to frequency. the higher the frequency the higher the energy of the photon and vice-versa.

4 0
4 years ago
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. A projectile is fired with an initial velocity of 113 m słatan angle of 60.0
bonufazy [111]

Answer:

a) 9.99 s

b) 538 m

c) 20.5 s

d) 1160 m

Explanation:

Given:

x₀ = 0 m

y₀ = 49.0 m

v₀ = 113 m/s

θ = 60.0°

aₓ = 0 m/s²

aᵧ = -9.8 m/s²

a) At the maximum height, the vertical velocity vᵧ = 0 m/s.  Find t.

vᵧ = aᵧ t + v₀ᵧ

(0 m/s) = (-9.8 m/s²) t + (113 sin 60.0° m/s)

t ≈ 9.99 s

b) At the maximum height, the vertical velocity vᵧ = 0 m/s.  Find y.

vᵧ² = v₀ᵧ² + 2aᵧ (y − y₀)

(0 m/s)² = (113 sin 60° m/s)² + 2 (-9.8 m/s²) (y − 49.0 m)

y ≈ 538 m

c) When the projectile lands, y = 0 m.  Find t.

y = y₀ + v₀ᵧ t + ½ aᵧ t²

(0 m) = (49.0 m) + (113 sin 60° m/s) t + ½ (-9.8 m/s²) t²

You'll need to solve using quadratic formula:

t ≈ -0.489, 20.5

Since negative time doesn't apply here, t ≈ 20.5 s.

d) When the projectile lands, y = 0 m.  Find x. (Use answer from part c).

x = x₀ + v₀ₓ t + ½ aₓ t²

x = (0 m) + (113 cos 60° m/s) (20.5 s) + ½ (0 m/s²) (20.5 s)²

x ≈ 1160 m

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3 years ago
Which statement explains how planets move in orbit as supported by Newton’s first law of motion?
GuDViN [60]

Answer:

C

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