1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
almond37 [142]
4 years ago
12

(99 Points) In the Position versus Time Graph of an object moving in a straight line, does the graph show acceleration during th

e interval from time equals two hours to time equals three hours?

Physics
2 answers:
hoa [83]4 years ago
6 0
In position time graphs, otherwise known as distance time graphs, acceleration/decceleration occurs when the line curves, which looks like the picture I've included.

In hours 2 to 3, the object does not accelerate, but instead stays at a constant speed of 20m per hour.

azamat4 years ago
5 0
No, the object is not accelerating because acceleration occurs if the object has a change in speed or direction. 
You might be interested in
As a space shuttle moves through the dilute ionized gas of Earth's ionosphere, the shuttle's potential is typically changed by -
zvonat [6]
Wndgkddhkgyrokydkyugpuflyl
5 0
3 years ago
How many micrometers are there in 4cm
ozzi

Answer:

40000

Explanation:

5 0
3 years ago
Read 2 more answers
A pickup truck has a width of 79.0 in. If it is traveling north at 42 m/s through a magnetic field with vertical component of
bekas [8.4K]

Answer:

The magnitude of the induced Emf is 0.003371V

Explanation:

The width of the truck is given as 79inch but we need to convert to meter for consistency, then

The width= 79inch × 0.0254=2.0066 metres.

Now we can calculate the induced Emf using expresion below;

Then the induced EMF= B L v

Where B= magnetic field component

L= width

V= velocity

=(40*10^-6) × (42) × (2.0066)

=0.003371V

Therefore, the magnitude emf that is induced between the driver and passenger sides of the truck is 0.003371V

8 0
4 years ago
If the gravitational field strength at the top of Mount Everest is 9.772 N/kg, approximately how tall (in feet) is
Delicious77 [7]

Answer:

The height of the Everest mountain is, x =  8514.087 m

Explanation:

Given data,

The gravitational field strength at the top of mount Everest, gₓ = 9.772 m/s²

The formula for gravitational field strength is,

                               <em> gₓ = GM/(R+x)²</em>

Where, x is the height from the surface of the Earth

Therefore,

                                (R+x)² = GM/gₓ

                                     x = √(GM/gₓ) - R

Substituting the values,

                       x = √(6.67408 x 10⁻¹¹ X  5.972 x 10²⁴ / 9.772) - 6.378 x 10⁶

                       x =  8514.087 m          

Therefore, the height of the Everest mountain is, x =  8514.087 m                                                              

6 0
3 years ago
How far will a car travel in 15 minutes at 20 m/s?
labwork [276]

Answer:

15×60×20 = 18000m / 18km

3 0
4 years ago
Other questions:
  • A student measures the electric flux through a closed spherical surface of volume V to be X. She then removes the charge from in
    7·1 answer
  • How do you calculate the Actual Mechanical Advantage (AMA) of a pulley?
    9·2 answers
  • A 32.5 g cube of aluminum initially at 45.8 °C is submerged into 105.3 g of water at 15.4 °C. What is the final temperature of b
    10·1 answer
  • What is 16.558 m/s rounded to three significant figures?
    8·1 answer
  • A deep space probe travels in a straight line at a constant speed of over 16,000 m/s. Assuming there is no friction in space, if
    10·1 answer
  • 48 POINTS
    15·1 answer
  • 5. Why did people change the Bronx River in the past?​
    7·1 answer
  • A wheel starts from rest at an angle of zero, and has
    13·1 answer
  • If an object with a mass of 248kg is lifted 76 meters in 18 seconds, how much power is used?
    6·1 answer
  • On the basis, a given figure, calculate rfficiency of the lever. ​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!