Complete Question
A Jaguar XK8 convertible has an eight-cylinder engine. At the beginning of its compression stroke, one of the cylinders contains 499cm3 of air at atmospheric pressure (1.01×105Pa) and a temperature of 27.0∘C. At the end of the stroke, the air has been compressed to a volume of 46.2cm3 and the gauge pressure has increased to 2.72×106Pa. Compute the final temperature.
Answer:
The final temperature is
Explanation:
From the question we are given
The volume of one of the cylinders is
The atmospheric pressure is
The temperature is
Volume at the end of the stroke is
The increased pressure is
Now to obtain the temperature we are going to apply the ideal gas equation to this question and this is mathematically given as
Where P is the pressure , V sis the volume T is the temperature
While is the rate constant and n is the number of mole which is constant in this question hence
=>
Making the subject of the formula we have
Therefore
Answer:
<h3>Law of reflection</h3>
Explanation:
According to the laws of reflection,
- Incident ray, reflected ray and normal lie on the same plane.
- Angle of reflection and angle of incidence are always equal.
→ Angle of reflection : Angle of which light rays reflect off surface.
→ Angle of incidence : Angle at which light rays strikes the surface.
Answer:
dont know what that is too much static
Explanation:
Problem # 1
Do heavier objects fall more slowly than lighter objects?
Answer
No. If an object is heavier the force of gravity is greater, but since it has greater mass the acceleration is the same, so it moves at the same speed (if we neglect air resistance). If we look at Newton's second law, F = ma. The force of gravity is F = mg, where m is the mass of the object and g is the acceleration due to gravity.
Equating, we have mg = ma. Therefore, a = g.
If there was no air resistance, a feather would fall at the same speed as an apple
Answer:
370.3J
Explanation:
A 10 kg ball is rolled to the top of a hill 37 m high using 4000 J of work. How much energy was lost due to heat?
Step one:
given data
mass m= 10kg
height of the hill= 37m
work done= 4000J
Step two:
The quantity of energy loss due to heat is the same as the difference in the potential energy possed by the mass and the work done
PE= mgh
PE=10*9.81*37
PE= 3629.7J
Hence the energy loss is
= 4000-3629.7
=370.3J