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SSSSS [86.1K]
3 years ago
12

A nuclear power plant has two independent safety systems. The probability the first will not operate properly in an emergency P

(A) is 0.01, and the probability the second will not operate P (B) in an emergency is 0.03. What is the probability that in an emergency both of the safety systems will not operate?
A. 3
B. 0.03
C. 0.0003
D. None of the choices are correct
Mathematics
2 answers:
BabaBlast [244]3 years ago
5 0
Each system is independent of one another, so you multiply the probabilities of failure for each

P(A and B)  = P(A)*P(B)
P(A and B) = 0.01*0.03
P(A and B) = 0.0003

Answer: Choice C
navik [9.2K]3 years ago
3 0
The systems are independent and function independently.  The joint probability in question is 0.01*0.03 = 0.0003.
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A blue die and a red die are thrown. B is the event that the blue comes up with a 6. E is the event that both dice come up even.
iVinArrow [24]

Answer:

Size of |E n B| = 2

Size of |B| = 1

Step-by-step explanation:

<em>I'll assume both die are 6 sides</em>

Given

Blue die and Red Die

Required

Sizes of sets

- |E\ n\ B|

- |B|

The question stated the following;

B = Event that blue die comes up with 6

E = Event that both dice come even

So first; we'll list out the sample space of both events

B = \{6\}

E = \{2,4,6\}

Calculating the size of |E n B|

|E n B| = \{2,4,6\}\ n\ \{6\}

|E n B| = \{2,4,6\}

<em>The size = 3 because it contains 3 possible outcomes</em>

Calculating the size of |B|

B = \{6\}

<em>The size = 1 because it contains 1 possible outcome</em>

8 0
3 years ago
of the computer games lynn has 5/12 are sports games and 3/12 are educational what fraction of the games are either sports or ed
nikklg [1K]
5/12 + 3/12 = 8/12

8/12 of the games are either sports or educational.
7 0
3 years ago
ANSWER PLEASE !!!!!!<br>​
Ilia_Sergeevich [38]

Answer:

B= 40 degress

Step-by-step explanation:

1x+ 5xc /3xc = 40

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3 years ago
If x=4cos(2t) and y=4sin(2t), what is the parameter of these equations
kobusy [5.1K]

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Step-by-step explanation:

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2x + y = 15 x + y = 10​
Artyom0805 [142]

Answer:

2x+y=15x+y=10

Consider the first equation. Subtract 15x from both sides.

2x+y−15x=y

Combine 2x and −15x to get −13x.

−13x+y=y

Subtract y from both sides.

−13x+y−y=0

Combine y and −y to get 0.

−13x=0

Divide both sides by −13. Zero divided by any non-zero number gives zero.

x=0

Consider the second equation. Insert the known values of variables into the equation.

15×0+y=10

Multiply 15 and 0 to get 0.

0+y=10

Anything plus zero gives itself.

3 0
3 years ago
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