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2 years ago

9

What is the value of x? Enter your answer in the box. X=

2 answers:

liubo4ka [24]2 years ago

8 0

Answer:52

Step-by-step explanation:

Blizzard [7]2 years ago

4 0

Value of X is 1 lemme know

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Which of the following is the graph of y=1/2X ?

ivanzaharov [21]

Where’s the graph?????

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2 years ago

Read 2 more answers

-6x-7=3x+11 how to solve this problem

Shalnov [3]

You have to get the x to one side so you'll subtract 3x from -6x and 3x from 3x, the 3x will cancel out and -6x - 3x is -9x-7=11, you have to add 7 from both sides the 7+7 cancels out and also add 11+7 which leaves -9x=18, you have to divide -9x/-9 and do 18/-9, which gets you x=-2. Here's the work shown if you didn't what i said...
-6x-7=3x+11
-3x -3x
-9x-7=11
+7 +7
-9x=18
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2 years ago

Solve for x then y.<br> y+10=-1/6(x-6)

VikaD [51]

Answer:

y= -x/6-9

x= -6y-54

Step-by-step explanation:

7 0

2 years ago

Please help!! MathsWatch, Surd Expressions, Clip 207c

dexar [7]

Answer:

$A=(72+36\sqrt{3})\ mm^2$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

$b=AB+BC+CD+DE$ ----> by segment addition postulate

substitute

$b=3+3+3+3=12\ mm$

step 2

Find the height of rectangle

$a=FB+CG+GH$ ---> by segment addition postulate

substitute the given values

$a=3+CG+3\\a=6+CG$

Find the length sides CG

Applying the Pythagorean Theorem

$BG^2=BC^2+CG^2$

substitute the given values

$6^2=3^2+CG^2$

$CG^2=6^2-3^2$

$CG=\sqrt{27}\ mm$

simplify

$CG=3\sqrt{3}\ mm$

therefore

$a=(6+3\sqrt{3})\ mm$

step 3

Find the area of rectangle

$A=ab$

we have

$a=(6+3\sqrt{3})\ mm$

$b=12\ mm$

substitute

$A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2$

8 0

3 years ago

The dimensions in inches of a shipping box at we ship 4 you can be expressed as width x, length x+5, and height 3x-1. The volume

MakcuM [25]

Answer:

Connexus: C,D,C,A,A.

Step-by-step explanation:

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3 years ago