? it’s already rounded, is there supposed to be a decimal?
Answer:
A. The graphs are the same.
Step-by-step explanation:
Answer: I'm pretty sure I can help, just give me like 3 minutes..
-Angie
<h2>
Step-by-step explanation:</h2>
As per the question,
Let a be any positive integer and b = 4.
According to Euclid division lemma , a = 4q + r
where 0 ≤ r < b.
Thus,
r = 0, 1, 2, 3
Since, a is an odd integer, and
The only valid value of r = 1 and 3
So a = 4q + 1 or 4q + 3
<u>Case 1 :-</u> When a = 4q + 1
On squaring both sides, we get
a² = (4q + 1)²
= 16q² + 8q + 1
= 8(2q² + q) + 1
= 8m + 1 , where m = 2q² + q
<u>Case 2 :-</u> when a = 4q + 3
On squaring both sides, we get
a² = (4q + 3)²
= 16q² + 24q + 9
= 8 (2q² + 3q + 1) + 1
= 8m +1, where m = 2q² + 3q +1
Now,
<u>We can see that at every odd values of r, square of a is in the form of 8m +1.</u>
Also we know, a = 4q +1 and 4q +3 are not divisible by 2 means these all numbers are odd numbers.
Hence , it is clear that square of an odd positive is in form of 8m +1
Answer:
{2, 6, 14}
Step-by-step explanation:
Using f(x) = 4x + 6 with a domain of {-1, 0, 2 }, find the range.
To get the range, we will substitute the values of the domain into the given function as shown;
when x = -1
f(-1) = 4(-1)+6
f(-1) = -4+6
f(-1) = 2
when x = 0
f(0) = 4(0)+6
f(0) = 0+6
f(0) = 6
when x = 2
f(2) = 4(2)+6
f(2) = 8+6
f(2) = 14
Hence the required range are {2, 6, 14}
