I’m pretty sure you just use pythag for that so 1.5^2 + h^2 = 2.5^2 and once you solve that you should have your answer and don’t forget to root it after
9514 1404 393
Answer:
8000π mm^3/s ≈ 25,133 mm^3/s
Step-by-step explanation:
The rate of change of volume is found by differentiating the volume formula with respect to time.
V = 4/3πr^3
V' = 4πr^2·r'
For the given numbers, this is ...
V' = 4π(20 mm)^2·(5 mm/s) = 8000π mm^3/s ≈ 25,133 mm^3/s
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<em>Additional comment</em>
By comparing the derivative to the area formula for a sphere, you see that the rate of change of volume is the product of the area and the rate of change of radius. This sort of relationship will be seen for a number of different shapes.
Answer:
LCM of 95 and 14 is 1330
Step-by-step explanation:
refer to the picture for explanation
Answer:
17.9 m/s
Step-by-step explanation:
Volume of the slick = 0.5 x π r² h--------------------------------- (1)
Where r = radius of slick
h = thickness of slick, 10⁻⁶m
If 0.5m³ of oil leaked, then the radius of the semicircular slick can be calculated from equation (1)
V = 0.5 x π r² h
0.5= 0.5 x π x r² x 10⁻⁶
r² = 10⁶/ π
r = 10³/√π
dV/dt = πrh dr/dt + 0.5π r² dh/dt----------------------------------- (2)
Asumming the film thickness is constant , equation (2) becomes
dV/dt = πrh dr/dt-------------------------------- (3)
dV/dt = 0.1m³/day
r= 10³/√π
dr/dt= rate of expansion of the slick
Substituting into (3);
0.1 = π x 10³/√π x 10⁻⁶ x dr/dt
dr/dt = 0.1 x 10⁶/ ( π x 10³/√π)
= 17.9479 m/s
≅ 17.9 m/s
