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raketka [301]
4 years ago
9

Is the inequality always, sometimes or never true?

Mathematics
1 answer:
Feliz [49]4 years ago
5 0
1 )  9 x + 18 > 9 x - 27
9 x - 9 x > - 27 - 18
0 * x > - 45
Always true
2 ) 6 x - 13 < 9 x - 12
6 x - 6 x < - 12 + 13
0 * x < 1
Always true
3 ) - 6 ( 2 x - 10 ) + 12 x ≤ 180
- 12 x + 60 + 12 x ≤ 180
0 * x ≤ 180 - 60
0 * x ≤ 120
Always true. 
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Tell whether the triangle with the given side lengths is a right triangle.
kramer

Answer:

no

Step-by-step explanation:

so in order for it to be a right triangle this would have to be true:

a^2 + b^2 = c^2

since c represents the hypoteneuse, it will be the longest side. so:

60^2 + 63^2 = 88^2

3600 + 3969 = 7744

7569 = 7744

since that statement is not true, the answer is no.

it is not a right triangle  

the square root of 7569 is 87, so the triple would have to be : {60,63,87}

4 0
3 years ago
How might this number be shown on a calculator?<br> 4.117x10-29
Sergio [31]

Answer:

12.17

Step-by-step explanation:

4 0
3 years ago
5. Veronika works at Future Shop and earns $10.50/h plus 6% commission on sales. Last week Veronika worked 40
Harlamova29_29 [7]
I believe it is $2470
3 0
3 years ago
Jake manages one of the flower shops. He wants to use the camations
love history [14]

Answer:

first you much determine the largest common factor of 16 and 60, which is 4.  This means that 4 can be divided evenly into both 16 and 60 and that 4 is the maximum number of flowers for each arrangement.  

Next you divide 16 by 4 to get the total number of arrangements of roses (16/4= 4 arrangements), and

divide 60 by 4 to get the total number of arrangements of carnations (60/4= 15 arrangements).

This means that Kyle can make a total of 19 arrangements (4+15=19).F

Step-by-step explanation:

hope this helps:0

6 0
3 years ago
Find the limit<br> Picture below
pogonyaev

Answer:

a. 4

Step-by-step explanation:

We want to find;

\lim_{h \to 0} \frac{f(2+h)-f(2)}{h}

If f(x)=x^2.

f(2+h)=(2+h)^2

f(2+h)=4+4h+h^2

Also;

f(2)=2^2

f(2)=4

This implies that;

\lim_{h \to 0} \frac{4+4h+h^2-4}{h}

Simplify;

\lim_{h \to 0} \frac{4h+h^2}{h}

Factor to get;

\lim_{h \to 0} \frac{h(4+h)}{h}

Cancel the common factors.

\lim_{h \to 0} 4+h

Substitute h=0 to get

\lim_{h \to 0} 4+h=4+0=4

7 0
4 years ago
Read 2 more answers
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