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raketka [301]
3 years ago
9

Is the inequality always, sometimes or never true?

Mathematics
1 answer:
Feliz [49]3 years ago
5 0
1 )  9 x + 18 > 9 x - 27
9 x - 9 x > - 27 - 18
0 * x > - 45
Always true
2 ) 6 x - 13 < 9 x - 12
6 x - 6 x < - 12 + 13
0 * x < 1
Always true
3 ) - 6 ( 2 x - 10 ) + 12 x ≤ 180
- 12 x + 60 + 12 x ≤ 180
0 * x ≤ 180 - 60
0 * x ≤ 120
Always true. 
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MATH :((<br>how do the chart??<br><img src="https://tex.z-dn.net/?f=%20-%20x%20%20%5E%7B2%7D%20%20-%209%20%5Cgeqslant%200" id="T
siniylev [52]

Answer:

<h2>no solution</h2>

Step-by-step explanation:

-x^2-9\geq0\qquad\text{change the signs}\\\\x^2+9\leq0\\\\\text{the parabola}\ x^2\ \text{is op}\text{en up and shifted 9 units up. Therefore is whole}\\\text{over the x-axis (only positive values)}.\\\\\bold{CONCLUSION}:\\\\\bold{no\ solution}

5 0
3 years ago
Consider the sequence 3, -9, 27, -81 what an explicit formula for the sequence
Nataly_w [17]
-(-3)power (n )
n is 1;2;3;4;....

6 0
3 years ago
PLEASE HELP ME!!!!!!
Nata [24]

9514 1404 393

Answer:

  vertex: (2, -3.2)

  axis of symmetry: x = 2

  zeros: x=0, x=4

  formula for axis of symmetry:

  • x = <x-coordinate of vertex>
  • x = -b/(2a) . . . . . . . where the quadratic is ax^2 +bx +c
  • x = average of zeros, (z1 +z2)/2

Step-by-step explanation:

a) The vertex x-coordinate is halfway between the zeros, so is x = (0+4)/2 = 2. It is where the graph has a turning point.

The vertex y-coordinate is the low point of this graph. It is not on a grid line, so we can only guess at its value. I choose to call it -3.2.

The vertex is (2, -3.2).

__

b) The axis of symmetry is the vertical line through the vertex. The constant in its equation is the x-coordinate of the vertex:

  x = 2

__

c) The zeros of the function are where the function crosses the x-axis. These are marked on the graph with red dots. The zeros are x=0 and x=4.

__

d) When the quadratic is written in standard form, ax^2 +bx +c, the equation of the axis of symmetry is ...

  x = -b/(2a) . . . . . perhaps this is the formula you're being asked for (?)

When there is no equation, the axis of symmetry can be found from the graph a couple of ways. One is to identify the x-coordinate of the vertex.

  x = <x-coordinate of the vertex>

Another is to average the zeros, since they are symmetrical about the axis of symmetry.

  x = average of zeros = (z1 +z2)/2

If the quadratic is written in vertex form, the vertex coordinate is the constant in the equation for the axis of symmetry.

  y = a(x -h)^2 +k . . . . . quadratic with vertex (h, k)

  x = h . . . . . . equation of axis of symmetry

8 0
2 years ago
I'LL GIVE YOU BRAINIEST!<br> 1 1/5 · x/3 = 9/10 solve for x
joja [24]

\huge\text{Hey there!}

\huge\textbf{Equation:}

\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\huge\textbf{Solve:}

\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{1\times5+1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{5 + 1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{6}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\huge\textbf{Simplify it:}

\mathbf{\rightarrow \dfrac{2}{5}x = \dfrac{9}{10}}

\huge\textbf{Multiply \boxed{\bf \dfrac{5}{2}} to both sides:}

\mathbf{\rightarrow \dfrac{5}{2}\times \dfrac{2}{5}x = \dfrac{5}{2}\times \dfrac{9}{10}}

\huge\textbf{Simplify it:}

\mathbf{\rightarrow x = \dfrac{5}{2}\times \dfrac{9}{10}}

\mathbf{\rightarrow x = \dfrac{5\times9}{2\times10}}

\mathbf{\rightarrow x = \dfrac{45}{20}}

\mathbf{\rightarrow x = \dfrac{45\div5}{20\div5}}

\mathbf{\rightarrow x = \dfrac{9}{4}}

\mathbf{x \approx 2 \dfrac{1}{4}}

\huge\textbf{Therefore, your answer should be:}

\huge\boxed{\mathsf{x = }\frak{2 \dfrac{1}{4}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

8 0
2 years ago
Read 2 more answers
Which ordered pair is the solution to the system of equations?
SOVA2 [1]
To find the solution, we use the substitution method. 

x+y=-1
<span>x-3y=11
</span>
x+y = -1-y
  -y       

x = -1-y

Now apply the value of x into the other equation.

x-3y=11
-1-y-3y = 11

Combine like terms

-4y -1 = 11
       +1    +1
-4y = 12

-4y = 12
-4y/-4 = 12/-4
y = -3

Now, apply the value of Y to one equation to find x.

y = -3

x -3 = -1
   +3   +3  
 
x= 2

Now we have the value for both, x and y.
x = 2
y =-3

Final answer: A. <span>(2, −3)</span>
3 0
3 years ago
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