Aminotes include synapsids and sauropsids as well as their ancestors, back to amphibians.
<span> Basically the male will have CC, the hen will have cc, and neither of them will have I. The key thing is that _all_ the chicks are coloured.
The male must have at least 1 C to be coloured, and cannot possess the dominant I. The hen has cc and/or an I to not be coloured.
That one chick is coloured would tell you little - only that the hen couldn't have 2 inhibitor alleles because otherwise the chick would have to have one and it doesn't.
However, for all of many chicks to be coloured, that means that the hen can't have any inhibitor alleles (otherwise around 50% would be white for that reason alone).
So to be colourless, the hen must be cc. However, if the male had only 1 colour allele (ie it was Cc) that would still mean that 50% of the chicks would be Cc (daddy's 'c' and one of mummy's 'c's).
Hope this helps please award brainly :)
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Answer:
Receptor-mediated endocytosis is a form of endocytosis in which receptor proteins on the cell surface are used to capture a specific target molecule. The receptors, which are transmembrane proteins, cluster in regions of the plasma membrane known as coated pits.
Explanation:
hope this is the answer that you look for
Answer:
all of the above
Explanation:
everytime u see all of the above its most likely the answer
Punnet squares are your friend with these kinds of questions :)
<u> A | a |</u>
A <u>| AA | Aa |</u>
a <u>| Aa | aa |</u>
Now we can easily see that 1/4 of the offspring will be AA, 1/2 will be Aa, and 1/4 will be aa. Therefore, it is the third answer that's correct (1/4 AA, 1/2 Aa, 1/4 aa). Hope this helps! :)
