Answer:
1 I think, read the explanation.
Explanation:
Offspring need to carry just one dominant allele from their parents to inherit the polydactyl condition. The probability of the offspring having polydactyly is 50% (2 of the 4) and 50% not having it (normal). This can be expressed as a ratio, 2:2 which can be simplified to 1:1. - found on the internet
A list of the cell fibers from largest to smallest would read:
1. microtubules – is a microscopic tubular structure that is present in numbers in the cytoplasm of cells. These are usually aggregated to form complex structures.
<span>2. intermediate filaments – are cytoskeletal components that is usually found in the cells of vertebrate species and </span>other organisms like plants, fungi, unicellular organisms.
3. <span>Microfilaments – are filamentous structures that can be found in the cytoplasm of eukaryotic cells and it will form part of the </span>cytoskeletons<span>. They are composed primarily of polymers of actin. But in cells, they usually interact with other proteins.</span>
The correct answer is microglia.
<span>Microglia is glial cells found in the central nervous system with the protective role. Because they are the resident macrophage cells, they act as the first and main form of active immune defense. Microglia is constantly cleaning the CNS for plaques, damaged or unnecessary neurons, and infectious agents, like viruses or other microorganisms.</span>
Answer:
1. G° = -RT ln (G1P/P)
3.1 = 8.314 × 310 × ln (G1P/P)
3.1 / 2577.34 = ln (G1P/P)
0.0012 = ln (G1P/P)
0.0012 = (log G1P/P)/log 2.71828
0.4342 × 0.0012 = log G1P/P
0.00052 = log G1P/P
G1P/P = 10^0.00052 = 1.0012
P/G1P = 1/1.0012 = 0.9988
2. The cleavage of glycogen phosphorolytically is beneficial for the cell to conduct the process as the discharged glucose is phosphorylated. A general hydrolytic cleavage would give rise to only a glucose, which has to be phosphorylated again with the help of ATP.
Another merit of phosphorylated glucose is that it comprises the negative charge and cannot diffuse out of the muscle cell. Thus, the reaction will not be at equilibrium under the physiological conditions and always encourages the generation of the products. The formation of products will amend the change in free energy in such a manner that the reaction will always carry in the forward direction.
3. Greater the ratio of [Pi]/[glucose-1-phosphate], higher will be the relative rate of glycogen phosphorylase in comparison to the phosphoglucomutase as the transformation of Glu-1-P becomes slow because of lesser accessibility of substrate.
Answer:
it will option D bcs force is zero
