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Dimas [21]
3 years ago
11

4.4 is what % of 25 ​

Mathematics
2 answers:
kirza4 [7]3 years ago
8 0

4.4 = .044

0.044x25 = 1.1

ANSWER = 1.1

sdas [7]3 years ago
3 0

Answer:17.6

Step-by-step explanation:

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Points A, B, C, and D are connected by segments.
Verizon [17]

Answer:

c

Step-by-step explanation:

I think its c

I'm not sure

4 0
3 years ago
Use Newton's Method to approximate the zero(s) of the function. Continue the iterations until two successive approximations diff
Nana76 [90]

Answer:

Poop

Step-by-step explanation:

4 0
3 years ago
Match them together to correct answer
Verizon [17]

ANSWER

Frequency=2

Midline =3

Amplitude =5

Period =π

EXPLANATION

We have:

f(x) = 5 \cos(x)  + 3

The given function is of the form;

f(x) = a\cos(bx)  + c

where

a=|5| =5 is the amplitude

and b=2 is the frequency.

and 2π/b=2π/2=π

The range of the given function is

8≤y≤-2

The midline is

\frac{8  + - 2}{2}  =  \frac{6}{2}  = 3

6 0
3 years ago
Read 2 more answers
All questions to be solved using linear combination.
monitta
1)
I:x-y=-7
II:x+y=7

add both equations together to eliminate y:
x-y+(x+y)=-7+7
2x=0
x=0

insert x=0 into II:
0+y=7
y=7

the solution is (0,7)

2)
I: 3x+y=4
II: 2x+y=5

add I+(-1*II) together to eliminate y:
3x+y+(-2x-y)=4+(-5)
x=-1

insert x=-1 into I:
3*-1+y=4
y=7

the solution is (-1,7)

3)

I: 2e-3f=-9
II: e+3f=18

add both equations together to eliminate f:
2e-3f+(e+3f)=-9+18
3e=9
e=3

insert e=3 into I:
2*3-3f=-9
-3f=-9-6
-3f=-15
3f=15
f=5

the solution is (3,5)

4)
I: 3d-e=7
II: d+e=5

add both equations together to eliminate e:
3d-e+(d+e)=7+5
4d=12
d=3

insert d=3 into II:
3+e=5
e=2

the solution is (3,2)

5)
I: 8x+y=14
II: 3x+y=4

add I+(-1*II) together to eliminate y
8x+y+(-3x-y)=14-4
5x=10
x=2

insert x=2 into II:
3*2+y=4
y=4-6
y=-2

the solution is (2,-2)
8 0
3 years ago
What is the solution to the equation 2x+4 - 12 = 20?<br> O X=0<br> O X=1<br> O X= 2<br> O X=9
Alex Ar [27]

Answer:

x = 14

Step-by-step explanation:

2x+4 - 12 = 20

2x - 8 = 20

2x = 28

x = 14

5 0
3 years ago
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