Ask question

Ask question

All categories

3 years ago

5

Find GCF of -50m ^4 n ^7 and 40m ^2 n ^10

1 answer:

trapecia [35]3 years ago

5 0

-50m^4 n^7 = 10m^2n^7(-5m^2)<span>
and
40m^2 n^10 = 10</span>m^2 n^7(4n^3)

Answer: GCF = 10m^2 n^7

You might be interested in

3/4 miles in 1/2 hour __ miles in 1 hour<br><br>

I am Lyosha [343]

Answer:

1.5 mile an hour

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

I WILL GIVE BRAINLEST IF YOU ANSWER BOTH WITH EXPLANATION please dont let me fail :(

Lapatulllka [165]

I see grey but if that’s black okay.
2/5

You had a 2/5 chance
He had a 1/4 chance

8 0

3 years ago

Read 2 more answers

Miguel borrowed $1,800for 2 years and ended up paying $180 in simple interest . What was the interest rate

Gala2k [10]

It was 10 % 1,800 ÷10 =180

3 0

3 years ago

Write 7 more than w is 25 as an algebraic equation.

ludmilkaskok [199]

Answer:

w+7=25

Step-by-step explanation:

if you need it solved its

w+7=25

-7 -7

w=18

8 0

3 years ago

Read 2 more answers

Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation

just olya [345]

Answer:

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation $v(t)= 6t^2-18t+12$ . We are asked to find the distance that the particle will travel in its first 2 seconds.

$s(t)=\int |v(t)|dt$

$s(t)=\int\limits^2_0 |6t^2-18t+12|dt$

Now, we will eliminate the absolute value sign as:

$s(t)=\int\limits^1_0 6t^2-18t+12dt+\int\limits^2_1 -6t^2+18t-12dt$

$s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1$

$s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1$

$s(2)=2(1)^3-9(1)^2+12(1)-(2(0)^3-9(0)^2+12(0))-2(2)^3+9(2)^2-12(2)-(-2(1)^3+9(1)^2-12(1))$

$s(2)=2-9+12-(0)-16+36-24-(-2+9-12)$

$s(2)=5-(0)-4-(-5)$

$s(2)=5-4+5$

$s(2)=6$

Therefore, the particle will travel 6 feet in first 2 seconds.

7 0

3 years ago